When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car.  Find a 99% confidence interval (CI) and margin of error (ME) for the true proportion of all college students who own a car.

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: A researcher found a 95% confidence interval for the proportion of college students who believe in…

A:

Q: Of 125 adults selected randomly from one town, 28 of them smoke. Construct a 99% confidence interval…

A: It is given that out of 125 adults in one town, 28 of them smoke. That is the value of n is 125 and…

Q: A sample of 60 people who were chosen for a sample had an average IQ score of 105. If the population…

A: From the given, x¯ (mean IQ score from sample)=105n (sample size)=60σ (population SD of IQ…

Q: In a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A: Given:  n=4026 x=708

Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: A poll reported that only 507 out of a total of 1809 adults in a particular region said they had a​…

A: The sampled no. of adults, i.e., the sample size, n=1809. The no. of sampled adults who expressed a…

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

A:

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: Using the 99% level of confidence, what is the confidence interval for proportion of students…

A: Let X be the random variable such number of students attending home football games. X = 750 N: Total…

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: A sample of 500 nursing applicants included 80 men.  Determine the 95% confidence interval for the…

A:

Q: A poll of 827 students at Alpha state college found that 61% of those polled preferred a quarter…

A: It is given that the proportion of the students who preferred a quarter system to a trimester…

Q: In a survey of 612 randomly selected female college students, 141 report that they had been sexually…

A: Given Information:n=612x=141c=95%=0.95

Q: A 95% confidence interval was found to be (14.312, 21.432). What is the margin of error? ME=

A: Answer: From the given data, 95% confidence interval was found to be (14.312, 21.432) lower limit =…

Q: The 90% confidence interval is from to. (Round to three decimal places as needed.)

A: A poll of 1030 adults in a country was conducted by telephone. Of those surveyed, 139 had…

Q: In a sample of 300 people, 154 said that they watched news on television. Find the 90% confidence…

A: According to the given information in this question We need to find the 90% confidence interval of…

Q: In a survey of 3260​ adults, 1456 say they have started paying bills online in the last year.…

A: Givenn=3260x=1456p^=xn=14563260=0.4466

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: The 95​% confidence interval for the proportion that express a great deal of confidence or quite a…

A: A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: A survey of 800 women shoppers found that 15% of them shop on impulse.  What is the 95% confidence…

A: n = 800p^ = 0.1595% CI for p = ?

Q: In a survey of 2745 ​adults, 1477 say they have started paying bills online in the last year.…

A: Given, n= 2745 x=1477 The sample proportion is given by: p^=xn=14772745=0.5381 Also, α=0.99…

Q: In a sample of 1901 patients who underwent a certain type of surgery, 22% experienced complications.…

A:

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year.…

A: Given, Therefore, As per z-distribution table the critical value of z at 0.01 level of significant…