Dry ice is solid carbon dioxide. Instead of melting, solid carbon
dioxide sublimes according to the equation:
CO2(s) ------------>CO2(g)
When dry ice is added to warm water, heat from the water causesthe dry ice to sublime more quickly. The evaporating carbon dioxide produces a dense fog often used to create special effects. In a simple dry ice fog machine, dry ice is added to warm water in a Styrofoam cooler. The dry
ice produces fog until it evaporates away, or until the water gets too cold to sublime the dry ice quickly enough. A small Styrofoam cooler holds
15.0 L of water heated to 85°C. Use standard enthalpies of formation to calculate the change in enthalpy for dry ice sublimation, and calculate the
mass of dry ice that should be added to the water so that the dry ice completely sublimes away when the water reaches 25 °C. Assume no heat loss to the surroundings. (The ∆H°f for CO2(s) is -427.4 kJ/mol.)
when I do this my final answer is 4903 grams which seems really high. Where am I going wrong?
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