### Practice Question on Solution Molarity#### Question:When dissolved in 0.500 L of water, which of the following would produce a solution with the greatest molarity?a. 20.0 g of KBr b. 20.0 g of NaBr c. 20.0 g of LiCl d. 20.0 g of CsCl#### Explanation:To determine which substance produces the solution with the greatest molarity, you'll need to use the formula for molarity (M):\[ M = \frac{n}{V} \]Here, \( n \) (number of moles) is calculated by dividing the mass of the solute by its molar mass (Molar Mass, \( M_{m} \)). The volume (\( V \)) is given as 0.500 L.The steps are as follows:1. Calculate the molar mass of each compound.2. Find the number of moles of each solute by dividing the given mass (20.0 g) by its molar mass.3. Calculate the molarity by dividing the number of moles by the volume of water (0.5 L).#### Solution:- **KBr (Potassium Bromide)** - Molar Mass: \( K (39.1) + Br (79.9) \approx 119 \ g/mol \) - Number of Moles: \( \frac{20.0 \ \text{g}}{119 \ \text{g/mol}} \approx 0.168 \ \text{mol} \) - Molarity: \( \frac{0.168 \ \text{mol}}{0.500 \ \text{L}} \approx 0.336 \ \text{M} \)- **NaBr (Sodium Bromide)** - Molar Mass: \( Na (23.0) + Br (79.9) \approx 103 \ g/mol \) - Number of Moles: \( \frac{20.0 \ \text{g}}{103 \ \text{g/mol}} \approx 0.194 \ \text{mol} \) - Molarity: \( \frac{0.194 \ \text{mol}}{0.500 \ \text{L}} \approx 0.388 \ \text{M} \

Answered: When dissolved in 0.500 L of water,…

When dissolved in 0.500 L of water, which of the following would produce a solution with the greatest molarity? a 20.0 g of KBr 20.0 g of NaBr 20.0 g of LICI d 20.0 g of CsCl O O O O

Chemical Principles in the Laboratory

11th Edition

ISBN:9781305264434

Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Chapter24: The Standardization Of A Basic Solution And The Determination Of The Molar Mass Of An Acid

Section: Chapter Questions

Problem 1ASA

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