alculate the molarity of the solute in the following solutions containing a. 1.25 g MgNH4PO4 in 750. mL solution Molarity = mol/L b. 18.1 g NaCH3COO in 500. mL solution Molarity = mol/L c. 9.65 g CaC2O4 in 250. mL solution Molarity = mol/L d. 2.58 g (NH4)2SO4 in 400. mL solution Molarity= mol/l

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Chapter1: Chemical Foundations
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**Calculate the molarity of the solute in the following solutions:**

a. **1.25 g MgNH₄PO₄ in 750. mL solution**  
   - Molarity = [______] mol/L

b. **18.1 g NaCH₃COO in 500. mL solution**  
   - Molarity = [______] mol/L

c. **9.65 g CaC₂O₄ in 250. mL solution**  
   - Molarity = [______] mol/L

d. **2.58 g (NH₄)₂SO₄ in 400. mL solution**  
   - Molarity = [______] mol/L

**Instructions:** For each solution, calculate the molarity by using the formula:

\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \]

Convert grams to moles using the molar mass of each compound, and convert milliliters to liters for your calculations.
Transcribed Image Text:**Calculate the molarity of the solute in the following solutions:** a. **1.25 g MgNH₄PO₄ in 750. mL solution** - Molarity = [______] mol/L b. **18.1 g NaCH₃COO in 500. mL solution** - Molarity = [______] mol/L c. **9.65 g CaC₂O₄ in 250. mL solution** - Molarity = [______] mol/L d. **2.58 g (NH₄)₂SO₄ in 400. mL solution** - Molarity = [______] mol/L **Instructions:** For each solution, calculate the molarity by using the formula: \[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \] Convert grams to moles using the molar mass of each compound, and convert milliliters to liters for your calculations.
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Molarity is defined as number of mole solute divide by volume of solution in liter 

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