alculate the molarity of the solute in the following solutions containing a. 1.25 g MgNH4PO4 in 750. mL solution Molarity = mol/L b. 18.1 g NaCH3COO in 500. mL solution Molarity = mol/L c. 9.65 g CaC2O4 in 250. mL solution Molarity = mol/L d. 2.58 g (NH4)2SO4 in 400. mL solution Molarity= mol/l
alculate the molarity of the solute in the following solutions containing a. 1.25 g MgNH4PO4 in 750. mL solution Molarity = mol/L b. 18.1 g NaCH3COO in 500. mL solution Molarity = mol/L c. 9.65 g CaC2O4 in 250. mL solution Molarity = mol/L d. 2.58 g (NH4)2SO4 in 400. mL solution Molarity= mol/l
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Calculate the molarity of the solute in the following solutions:**
a. **1.25 g MgNH₄PO₄ in 750. mL solution**
- Molarity = [______] mol/L
b. **18.1 g NaCH₃COO in 500. mL solution**
- Molarity = [______] mol/L
c. **9.65 g CaC₂O₄ in 250. mL solution**
- Molarity = [______] mol/L
d. **2.58 g (NH₄)₂SO₄ in 400. mL solution**
- Molarity = [______] mol/L
**Instructions:** For each solution, calculate the molarity by using the formula:
\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \]
Convert grams to moles using the molar mass of each compound, and convert milliliters to liters for your calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb692af84-21f3-4e00-9062-ab31ad5014d9%2F68a647c4-59b0-46cc-8f05-0f92e640b78c%2Fikqcmlf_processed.png&w=3840&q=75)
Transcribed Image Text:**Calculate the molarity of the solute in the following solutions:**
a. **1.25 g MgNH₄PO₄ in 750. mL solution**
- Molarity = [______] mol/L
b. **18.1 g NaCH₃COO in 500. mL solution**
- Molarity = [______] mol/L
c. **9.65 g CaC₂O₄ in 250. mL solution**
- Molarity = [______] mol/L
d. **2.58 g (NH₄)₂SO₄ in 400. mL solution**
- Molarity = [______] mol/L
**Instructions:** For each solution, calculate the molarity by using the formula:
\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \]
Convert grams to moles using the molar mass of each compound, and convert milliliters to liters for your calculations.
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Step 1
Molarity is defined as number of mole solute divide by volume of solution in liter
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