Answered: An aqueous solution of ethanol (MM =…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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An aqueous solution of ethanol (MM = 46.07 g/mol) has a molality of 12.15 m and a density of 1.100 g/mL. What is the molarity of ethanol in the solution?

Expert Solution

Step 1:- Calculation of number of moles of ethanol

$S o l u t i o n : T h e v a l u e s p r o v i d e d i n t h e q u e s t i o n a r e : i) M o l a r i t y o f e t h a n o l s o l u t i o n = 12.15 m i i) M o l a r m a s s o f e t h a n o l = 46.07 g / m o l i i i) D e n s i t y o f e t h a n o l s o l u t i o n = 1.100 g / m L L e t u s a s s u m e t h a t t h e m a s s o f s o l v e n t b e 100 g o r 0.1 K g w e k n o w t h a t, t h e f o r m u l a t o c a l c u l a t e m o l a r i t y o f e t h a n o l s o l u t i o n i s, M o l a r i t y o f e t h a n o l s o l u t i o n = \frac{N u m b e r o f m o l e s o f e t h a n o l}{M a s s o f s o l v e n t i n K g} o r N u m b e r o f m o l e s o f e t h a n o l = M o l a r i t y o f e t h a n o l s o l u t i o n x M a s s o f s o l v e n t i n k g = 12.15 m x 0.1 k g = 12.15 \frac{m o l}{k g} x 0.1 k g = 12.15 m o l x 0.1 = 1.215 m o l$

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