When active metals such as sodium are exposed to air, they quickly form a coating of metal oxide. The balanced equation for the reaction of sodium metal with oxygen gas is →→→→→2Na₂O(s) 4Na(s) + O₂(g) - Suppose a piece of sodium metal gains 2.05 g of mass after being exposed to air. Assume that this gain can be attributed to its reaction with oxygen. (a) What mass of O₂ reacted with the Na? men (b) What mass of Na reacted? (c) What mass of Na₂O formed?

World of Chemistry
7th Edition
ISBN:9780618562763
Author:Steven S. Zumdahl
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Chapter9: Chemical Quantities
Section: Chapter Questions
Problem 54A
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When active metals such as sodium are exposed to air, they
quickly form a coating of metal oxide. The balanced
equation for the reaction of sodium metal with oxygen gas is
4Na(s) + O₂(g)
2Na₂O(s)
Suppose a piece of sodium metal gains 2.05 g of mass
after being exposed to air. Assume that this gain can be
attributed to its reaction with oxygen.
(a) What mass of O₂ reacted with the Na?
(b) What mass of Na reacted?
(c) What mass of Na₂O formed?
01.0
Transcribed Image Text:When active metals such as sodium are exposed to air, they quickly form a coating of metal oxide. The balanced equation for the reaction of sodium metal with oxygen gas is 4Na(s) + O₂(g) 2Na₂O(s) Suppose a piece of sodium metal gains 2.05 g of mass after being exposed to air. Assume that this gain can be attributed to its reaction with oxygen. (a) What mass of O₂ reacted with the Na? (b) What mass of Na reacted? (c) What mass of Na₂O formed? 01.0
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