When a force Facts on an object at some distance r from a point P, called the pivot point, it can cause the object to rotate rather than translate. The ability of a force to cause rotation is called the torque about P due to the force F and is symbolized by the Greek lowercase letter tau T. Torque equals the cross product between the applied force F and the distance vector r = PQ that points from P to the point Q where F acts on the object. That is, T=rxF The figure shows a wrench that is being used to turn a nut and three separate forces that could be applied to the end of the wrench. The point P is at the origin of the coordinate system and the point Q is at the end of the wrench at (0.25, 0, 0), where the forces are applied. F₁ e F₂ 45° F3
When a force Facts on an object at some distance r from a point P, called the pivot point, it can cause the object to rotate rather than translate. The ability of a force to cause rotation is called the torque about P due to the force F and is symbolized by the Greek lowercase letter tau T. Torque equals the cross product between the applied force F and the distance vector r = PQ that points from P to the point Q where F acts on the object. That is, T=rxF The figure shows a wrench that is being used to turn a nut and three separate forces that could be applied to the end of the wrench. The point P is at the origin of the coordinate system and the point Q is at the end of the wrench at (0.25, 0, 0), where the forces are applied. F₁ e F₂ 45° F3
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![(b) Find the torque r about P due to each of the three forces shown in the figure. Assume that the magnitude of each force is
246 N and the wrench is 0.25 m long.
(Use symbolic notation and fractions where needed. Let T; be the torque due to F;.)
T1 = (0,0,61.5)
T₂ =
Incorrect
(0,0,61.5)
T3 = (0,0,0)
4
Question Source: Sullivan 2e Calculus](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7dc5cf65-67df-4a3e-8bae-308a2a2509c4%2F35044f78-d00f-4575-84b8-efd96c42737e%2F7m3vot_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(b) Find the torque r about P due to each of the three forces shown in the figure. Assume that the magnitude of each force is
246 N and the wrench is 0.25 m long.
(Use symbolic notation and fractions where needed. Let T; be the torque due to F;.)
T1 = (0,0,61.5)
T₂ =
Incorrect
(0,0,61.5)
T3 = (0,0,0)
4
Question Source: Sullivan 2e Calculus
![When a force F acts on an object at some distance r from a point P, called the pivot point, it can cause the object to rotate rather
than translate. The ability of a force to cause rotation is called the torque about P due to the force F and is symbolized by the
Greek lowercase letter tau T. Torque equals the cross product between the applied force F and the distance vector r = PQ that
points from P to the point Q where F acts on the object. That is,
T=rxF
The figure shows a wrench that is being used to turn a nut and three separate forces that could be applied to the end of the
wrench. The point P is at the origin of the coordinate system and the point Q is at the end of the wrench at (0.25, 0, 0), where
the forces are applied.
F₁4
Q
45°
F₂
F3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7dc5cf65-67df-4a3e-8bae-308a2a2509c4%2F35044f78-d00f-4575-84b8-efd96c42737e%2Fy8842luh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:When a force F acts on an object at some distance r from a point P, called the pivot point, it can cause the object to rotate rather
than translate. The ability of a force to cause rotation is called the torque about P due to the force F and is symbolized by the
Greek lowercase letter tau T. Torque equals the cross product between the applied force F and the distance vector r = PQ that
points from P to the point Q where F acts on the object. That is,
T=rxF
The figure shows a wrench that is being used to turn a nut and three separate forces that could be applied to the end of the
wrench. The point P is at the origin of the coordinate system and the point Q is at the end of the wrench at (0.25, 0, 0), where
the forces are applied.
F₁4
Q
45°
F₂
F3
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