When 50.0 g of oxygen gas (MW = 32.0) react excess diborane gas (B2H6; MW =D27.6), the enthalpy change is -1120 kJ. What is the enthalpy change for the reaction B2H6lg) + 3 O2lg) → B2O3(s) + 3 H20(1) AH° = ? O-2150 kJ -239 kJ -1120 kJ -717kJ Next ► « Previous

When 50.0 g of oxygen gas (MW = 32.0) react excess diborane gas (B2H6; MW =D27.6), the enthalpy change is -1120 kJ. What is the enthalpy change for the reaction B2H6lg) + 3 O2lg) → B2O3(s) + 3 H20(1) AH° = ? O-2150 kJ -239 kJ -1120 kJ -717kJ Next ► « Previous

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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When chemical A and chemical B are mixed together, and endothermic reaction below occurs:4A(aq) + 3B(s) --> 2C(aq)To find the enthalpy of this reaction, a scientist pours 155 mL of a 0.33 M solution A into abeaker and measures the temperature to be 20.1 ̊C. To this same beaker the scientist thenadds 3.75 g of substance B with stirring (molar mass of B is 33 g/mol), and finds thetemperature to now be 16.3 ̊C. Calculate the molar enthalpy of this reaction for every mole ofC produced.
Dimethyl ether, a useful organic solvent, is prepared in two steps. In the first step, carbon dioxide and hydrogen react to form methanol and water: CO2(g) + 3H2(g) --> CH3OH(I) + H2O(I) H=-131. kJ In the second step, methanol reacts to form dimethyl ether and water: 2CH3OH(I) ---> CH3OCH3(g) + H2O(I) H=8. kJ Calculate the net change in enthalpy for the formation of one mole of dimethyl ether from carbon dioxide and hydrogen from these reactions. Round your answer to the nearest kJ. = kJ
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How many grams of CaO must be added to 50.0 mL of water to make the temperature increase from 25.0 Â°C to 58.87 Â°C? The reaction is CaO(s) + H 2O(l) ↔ Ca(OH) 2(aq) -- ΔH = -83.7 kJAssume the heat capacity of the solution is the same as pure water (4.184 J/g*Â°C), the density of the solution is 1.00 g/mL and there is no loss of heat to the surroundings.
The value of AH° for the reaction below is -6535 kJ. ob kJ of heat are released in the combustion of 16.0 g of C6H6 (1)? MM C6H6 = 78.12 g/mol 2C6H6 (1) + 1502 (g) → 12CO2 (g) + 6H₂O (1) 1 A) 669 SHAHB)-6535 C) 1.34 x 103 D) 5.23 x 104 E) 2.68 x 103 Only typed solution.
Gasoline is composed primarily of hydrocarbons, includingmany with eight carbon atoms, called octanes. One ofthe cleanest–burning octanes is a compound called 2,3,4-trimethylpentane, which has the following structural formula: The complete combustion of one mole of this compoundto CO21g2 and H2O1g2 leads to ΔH° = -5064.9 kJ.(a) Write a balanced equation for the combustion of1 mol of C8H181l2. (b) By using the information inthis problem and data in Table 5.3, calculate ΔHf° for2,3,4-trimethylpentane.
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Consider the decomposition of hydrogen bromide to form hydrogen and gaseous bromine, Br2(g): HBr(g) 1/2 H2(g) + 1/2 Br2(g) H = 72.5 kJ (a) What is the enthalpy change for the reverse reaction?Hreverse = _____ kJ/mol(b) Balance the forward reaction with whole-number coefficients. What is H for the reaction represented by this equation?H = _____ kJ/mol
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