When 200.0 mL of 0.862 M HCI is mixed with 200.0 mL of 0.431 M Ba(OH)2 in a coffee cup calorimeter, the temperature of the solution increases from 21.35°C to 27.05°C. Given the specific heat of solution of 4.18 Jg °C- and assuming the density of each solution to be 1.00 g/mL, what is the heat of reaction in kJ per mole of HCI? The neutralization reaction is: 2 HCI(aq) + Ba(OH)2(aq) → BaCl2(aq) + 2 H20(1)

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When 200.0 mL of 0.862 M HCI is mixed with 200.0 mL of 0.431 M Ba(OH)2 in a coffee cup calorimeter, the temperature of the
solution increases from 21.35°C to 27.05°C. Given the specific heat of solution of 4.18 J g1 °C-l and assuming the density of
each solution to be 1.00 g/mL, what is the heat of reaction in kJ per mole of HCl?
The neutralization reaction is:
2 HCI(aq) + Ba(0H)2(aq) → BaCl2(aq) + 2 H20(1)
Select one:
-55.3 kJ/mol HCI
-9.53 kJ/mol HCI
O - 110.6 kJ/mol HCI
O 110.6 kJ/mol HCl
55.3 kJ/mol HCI
O 9.53 kJ/mol HCI
ВАCK
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Transcribed Image Text:When 200.0 mL of 0.862 M HCI is mixed with 200.0 mL of 0.431 M Ba(OH)2 in a coffee cup calorimeter, the temperature of the solution increases from 21.35°C to 27.05°C. Given the specific heat of solution of 4.18 J g1 °C-l and assuming the density of each solution to be 1.00 g/mL, what is the heat of reaction in kJ per mole of HCl? The neutralization reaction is: 2 HCI(aq) + Ba(0H)2(aq) → BaCl2(aq) + 2 H20(1) Select one: -55.3 kJ/mol HCI -9.53 kJ/mol HCI O - 110.6 kJ/mol HCI O 110.6 kJ/mol HCl 55.3 kJ/mol HCI O 9.53 kJ/mol HCI ВАCK Question 5 of 6 NEXT étv A
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