100.0 mL of 1.00 M HBr at 22.5 °C is combined with 100.0 mL of 1.00 M LiOH at 22.5 °C. The mixture reaches a temperature of 29.2 °C. Assume the density of the solutions is 1.00 g/mL and their specific heat capacity is the same as pure water. What is the molar heat of reaction?

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100.0 mL of 1.00 M HBr at 22.5 °C is combined with 100.0 mL of 1.00 M LiOH at 22.5 °C. The mixture reaches a temperature of 29.2 °C. Assume the density of the solutions is 1.00 g/mL and their specific heat capacity is the same as pure water. What is the molar heat of reaction?

Expert Solution
Step 1

100 mL of 1M of HBr reacts with 100 mL of 1M of LiOH and the reaction is as follows:

LiOH (aq) + HBr (aq)LiOH (aq) + H2O (l)

Step 2

Given, the initial temperature of the solution = 22.5 0C.

Final temperature of the solution = 29.2 0C.

Density = 1g/mL.

Mass of the solution = 200 g.

The heat of the reaction is calculated as follows:

q = m c T=200g ×4.184 J/C0×(29.2 -22.5)=5606.56 J

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