When 1.0105 g of an unknown was added, the freezing point of the solution was determined to be 41.8 °C. Calculate the change in the freezing point, and then calculate the molality of the solution. The Kf of lauric acid is 3.90 °C⁄?.
When 1.0105 g of an unknown was added, the freezing point of the solution was determined to be 41.8 °C. Calculate the change in the freezing point, and then calculate the molality of the solution. The Kf of lauric acid is 3.90 °C⁄?.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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When 1.0105 g of an unknown was added, the freezing point of the solution was determined to be 41.8 °C. Calculate the change in the freezing point, and then calculate the molality of the solution. The Kf of lauric acid is 3.90 °C⁄?.
![Temperature (°C)
70
65
60
55
50
45
40
35
30
Freezing Point Determination: Pure Solvent
4
0 20 40
A
。
60
100
80
Time (seconds)
120
140
160
Liquid cooling
y = -0.3333x + 63.2
R² = 0.9889
Liquid Freezing
y = -0.0255x+44.929
R² = 0.989
◆ Liquid Cooling
Freezing](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff967fe3e-7273-41d1-b0d5-41ab5bd397fd%2F135b4ed1-e0ee-4a0d-922a-c2eb80785ff8%2Fdgowc7i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Temperature (°C)
70
65
60
55
50
45
40
35
30
Freezing Point Determination: Pure Solvent
4
0 20 40
A
。
60
100
80
Time (seconds)
120
140
160
Liquid cooling
y = -0.3333x + 63.2
R² = 0.9889
Liquid Freezing
y = -0.0255x+44.929
R² = 0.989
◆ Liquid Cooling
Freezing
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