what's the correct answer? A ray passing through the center of a thin lens surrounded by air on both sidesa) is bent downwardb) is bent upwardc) does not change directiond) becomes parallel to the optical axise) becomes perpendicular to the optical axis
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what's the correct answer?
A ray passing through the center of a thin lens surrounded by air on both sides
a) is bent downward
b) is bent upward
c) does not change direction
d) becomes parallel to the optical axis
e) becomes perpendicular to the optical axis
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Solved in 2 steps with 2 images
- Spherical aberration is due to light rays O a. passing through the outer portions of a lens not focusing at the same point as rays that pass through the center O b. of different wavelength not focusing at the same point O C. passing through the lens in the vertical direction not focusing at the same point as rays passing through the lens in the horizontal direction O d. passing through the outer portions of a lens being absorbed more than rays that pass through the center6. A scuba diver training in a pool looks at his instructor as shown below. What angle does the ray from the instructor's face make with the perpendicular to the water at the point where the ray enters? The angle between the ray in the water and the perpendicular to the water is 25.0°. Also find the height of the instructor's head above the water, noting that you will first have to calculate the angle of incidence. (b) Find the apparent depth of the diver's head below water as seen by the instructor. + -2.0 m- +4 d = 2.0mIf the screen is at the right position and the object is in a right position, the lens will focus the image of the object onto the screen. If the screen is anywhere else, the object will look blurry or won't be seen. The optical table has a meter-tape attached to the side, to give the position of the items. If the object is in a wrong position, the lens will defocus the light -- spread it out. That means that the screen can't be placed anywhere to display a focused image. If xL = 32.7 cm and the focal length is f = 20.8 cm, give a position (xO) that results in the light from the object spreading out. (There are infinitely many such positions.)
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