A small tropical fish is at the center of a water-filled, spherical fish bowl 28.0 cm indiameter.a) Find the apparent position and magnification of the fish to an observer outsidethe bowl. The effect of the thin walls of the bowl may be ignored.b) A friend advised the owner of the bowl to keep it out of direct sunlight to avoidblinding the fish, which might swim into the focal point of the parallel rays fromthe sun. Is the focal point actually within the bowl?

The solution is attached below.Explanation:

Answered: A small tropical fish is at the center…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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a) Find an equation for the length L of a refracting telescope in terms of the focal length of the objective fo and the magnification m. L = (b) A knob adjusts the eyepiece forward and backward. Suppose the telescope is in focus with an eyepiece giving a magnification of 20.3. By what distance must the eyepiece be adjusted when the eyepiece is replaced, with a resulting magnification of 1.0 ✕ 102? Must the eyepiece be adjusted backward or forward? Assume the objective lens has a focal length of 2.32 m. (Use a positive value if the eyepiece must be moved forward toward the objective lens and negative values if the eyepiece must be moved backwards.) cm
= A leaf of length his positioned d below. Leaf d 70.3 cm in front of a converging lens with a focal length of 34.0 cm. An observer views the image of the leaf from a position 1.26 m behind the lens, as shown in the figure 1.26 m (a) What is the magnitude of the lateral magnification (the ratio of image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the leaf directly?
Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.
It is your first day at work as a summer intern at an optics company. Your supervisor hands you a diverging lens and asks you to measure its focal length. You know that with a converging lens, you can measure the focal length by placing an object a distance ss to the left of the lens, far enough from the lens for the image to be real, and viewing the image on a screen that is to the right of the lens. By adjusting the position of the screen until the image is in sharp focus, you can determine the image distance s′s′ and then use the equation 1s+1s′=1f1s+1s′=1f, to calculate the focal length ff of the lens. But this procedure won't work with a diverging lens−−by itself, a diverging lens produces only virtual images, which can't be projected onto a screen. Therefore, to determine the focal length of a diverging lens, you do the following: First you take a converging lens and measure that, for an object 20.0 cmcm to the left of the lens, the image is 29.7 cmcm to the right of the lens.…
The figure shows a refracted light beam in linseed oil making an angle of ? = 15.8° with the normal line NN'. The index of refraction of linseed oil is 1.48. a) Determine the angle ?. b) Determine the angle ?'.
1. A patient enters an eye doctor’s office and finds the doctor tells him that his near point is 10.0 cm. The doctor also finds the patient’s far point (with eyes relaxed) is 125 cm. Each eye lens can be assumed to be 2.00 cm from the retina. a) Between what limits (units: diopters) does the power of this patient’s lens (technically lens+cornea combination) vary? b) The doctor is going to prescribe glasses. Calculate the power of the eyeglass lens the patient should use for relaxed distance vision. Is the lens converging or diverging?
MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Your physics study partner is nearsighted. She has a near point of 50.0 cm from her eyes and she wears eyeglasses designed to allow her to read a newspaper held at a distance of 28.5 cm from her eyes. Determine the focal length of her glasses for each of the following cases. (a) She wears her eyeglasses 1.80 cm from her eyes. cm (b) She wears her eyeglasses 2.80 cm from her eyes. cm
Q1 a) The eyepiece of a refracting telescope has a focal length of 9.00cm. The distance between objective and eyepiece is 1.80m, and the final image is at infinity. What is the angular magnification of the telescope? F=580×10² 14
To fit a contact lens to a patient's eye, a keratometer can be used to measure the curvature of the cornea-the front surface of the eye. This instrument places an illuminated object of known size at a known distance p from the cornea, which then reflects some light from the object, forming an image of it. The magnification M of the image is measured by using a small viewing telescope that allows a comparison of the image formed by the cornea with a second calibrated image projected into the field of view by a prism arrangement. Determine the radius of curvature of the cornea whenp = 28.0 cm and M = 0.0140.
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A student stands dsub0=2.4 m in front of a floor-to-ceiling mirror. Her eyes are hsube=1.53 m above the floor and she holds a flashlight at a distance hsubf=.55 m above the floor. Calculate the angle in degrees that the flashlight makes with respect to the floor if the light is reflected into her eyes.
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