What would be the equilbrium potential for the ion K ina cell be it K+Joute 4 mM and K-jn= 155 mM? Given R8314472 molK T 3TC = 310 K F= 965- 104 Cmol O -908 mv 01283 mV d 665 mv For Reynolds number equals 1000, the flow is Lubulert Laminar

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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What would be the equilibrium potential for the ion K. in a cell be if (K+ Joute 4 mM and K-Jin= 155 mM7 Given: R 8314472 /molK, T= 3TC = 310 K F=
9.65-10^4 C/mol
908 mv
Ob1283 mV
98 mv
Od 665 mv
For Reynolds number equals 1000, the flow is
> Turbulent
b Laminar
Transcribed Image Text:What would be the equilibrium potential for the ion K. in a cell be if (K+ Joute 4 mM and K-Jin= 155 mM7 Given: R 8314472 /molK, T= 3TC = 310 K F= 9.65-10^4 C/mol 908 mv Ob1283 mV 98 mv Od 665 mv For Reynolds number equals 1000, the flow is > Turbulent b Laminar
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