What would be the approximate net charge of the peptide shown below at pH = 7.3? To facilitate answering this question, assume that the N-terminal aminium group has a pKa of 8, the C-terminal carboxyl group has a pK₂ of 3.5, and that the ionizable side chains have pKas as follows: Asp = 4.0, Glu = 4.0, His = 6, Cys = 8.4, Tyr = 10, Lys = 10, and Arg = 12.5. Also, assume that if the pH is at least two units above or below the pK₂ of a particular group, then that group is completely unprotonated or protonated, as the case may be. Report your answer to the nearest hundredth. H₂N. NH₂ OH N NH OH

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Chapter1: Chemical Foundations
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What would be the approximate net charge of the peptide shown below at pH = 7.3? To facilitate answering this question, assume that the
N-terminal aminium group has a pKa of 8, the C-terminal carboxyl group has a pK₂ of 3.5, and that the ionizable side chains have pKas as
follows: Asp = 4.0, Glu = 4.0, His = 6, Cys = 8.4, Tyr = 10, Lys = 10, and Arg= 12.5. Also, assume that if the pH is at least two units above or
below the pK₂ of a particular group, then that group is completely unprotonated or protonated, as the case may be. Report your answer to the
nearest hundredth.
H₂N.
NH₂
OH
N
NH
by
OH
Transcribed Image Text:What would be the approximate net charge of the peptide shown below at pH = 7.3? To facilitate answering this question, assume that the N-terminal aminium group has a pKa of 8, the C-terminal carboxyl group has a pK₂ of 3.5, and that the ionizable side chains have pKas as follows: Asp = 4.0, Glu = 4.0, His = 6, Cys = 8.4, Tyr = 10, Lys = 10, and Arg= 12.5. Also, assume that if the pH is at least two units above or below the pK₂ of a particular group, then that group is completely unprotonated or protonated, as the case may be. Report your answer to the nearest hundredth. H₂N. NH₂ OH N NH by OH
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