Consider a tripeptide (a peptide that's only 3 amino acids long) composed of one molecule each of lysine, leucine, and the hypothetical amino acid lupine (which doesn't actually exist, so don't try to look it up). Lupine has an ionizable side group with a pa of 6.3. When this tripeptide is dissolved in an aqueous solution at pH 5.0, the net charge on the molecule is +2. Give the charge on the protonated form of the lupine side group, and the charge on the deprotonated form of the lupine side group. show your work or explain how you determined the charge on each form of the lupine side groups
Neutral Amino Acids
Amino acids which do not have any charge on them are neutral amino acids.
Globular Protein
The globular proteins refer to the shape of protein specifically spherical in nature apart from spherical form fibrous, disordered and membrane-bound proteins exist. These globular proteins are miscible in water and form a colloidal solution rather than other types which might not exhibit solubility. Many classes of the fold are found in globular proteins, which render them a sphere shape. Globular fold containing proteins usually are referred to by the term globin.
Dimer
Dimers are basic organic compounds, which are derivates of oligomers. It is formed by the combination of two monomers which could potentially be strong or weak and in most cases covalent or intermolecular in nature. Identical monomers are called homodimer, the non-identical dimers are called heterodimer. The method by which dimers are formed is known as “dimerization”.
Dipeptide
A dipeptide is considered a mixture of two distinct amino acids. Since the amino acids are distinct, based on their composition, two dipeptide's isomers can be produced. Various dipeptides are biologically essential and are therefore crucial to industry.
3a) Consider a tripeptide (a peptide that's only 3 amino acids
long) composed of one molecule each of lysine, leucine, and the
hypothetical amino acid lupine (which doesn't actually exist, so
don't try to look it up). Lupine has an ionizable side group with a
pa of 6.3. When this tripeptide is dissolved in an aqueous
solution at pH 5.0, the net charge on the molecule is +2. Give
the charge on the protonated form of the lupine side group, and
the charge on the deprotonated form of the lupine side group.
show your work or explain how you determined
the charge on each form of the lupine side groups
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