Answered: What will happen if the parts of…

What will happen if the parts of ubiquitin-conjugating enzymes' parts change specifically the ( beta, sheet, and turns), will the change affect the function of ubiquitin-conjugating enzyme?

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section: Chapter Questions

Problem 20QP: If an extra nucleotide is inserted in the first exon of the beta globin gene, what effect will it...

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If an extra nucleotide is inserted in the first exon of the beta globin gene, what effect will it have on the amino acid sequence of the globin polypeptides? Will the globin most likely be fully functional, partly functional, or nonfunctional? Why?
Use the following information to answer the next question. The DNA strand shown below is thought to contain the genetic code for part of an enzyme B-galactosidase which is involved in lactose metabolism. (Read the DNA beginning at the left.) -A-T-A-T-G-G-G-G-C-A-T-G The second amino acid coded from the section of DNA for B-galactosidase is Select one: a. thymine b. tryptophan c. serine d. threonine
Failure of anti-oxidant function results in the hydroxylation of an aromatic acid of Enzyme Z and its activation, so that it degrades protoporphyrin to porphyrin, an unstable product. When hit by light, this product further degrades to form a compound responsible for the lesions and excruciating pain the man suffers. The mutation also affected an amino acid at the N-terminal of Enzyme X. Sequencing of the first seven (7) amino acids at the N-terminal of the normal enzyme gave the following sequence: trp-arg-asp-leu-ser-gly-his When the cDNA was sequenced by the Sanger method utilizing ddCTP, the following products were obtained: Tetranucleotide Hexanucleotide Nonanucleotide Decanucleotide Dodenucleotide Octadecanucleotide Nonadecanucleotide 21-nucleotide What is the sequence of the bases in the mRNA coding for the peptide above?
Failure of anti-oxidant function results in the hydroxylation of an aromatic acid of Enzyme Z and its activation, so that it degrades protoporphyrin to porphyrin, an unstable product. When hit by light, this product further degrades to form a compound responsible for the lesions and excruciating pain the man suffers. The mutation also affected an amino acid at the N-terminal of Enzyme X. Sequencing of the first seven (7) amino acids at the N-terminal of the normal enzyme gave the following sequence: trp-arg-asp-leu-ser-gly-his When the CDNA was sequenced by the Sanger method utilizing ddCTP, the following products were obtained: Tetranucleotide, Hexanucleotide, Nonanucleotide, Decanucleotide, Dodenucleotide, Octadecanucleotide, Nonadecanucleotide, 21-nucleotide What is the sequence of the bases in the mRNA coding for the peptide above? The mutation involved the 19 bases of the template strand of the peptide. A comparison of the electrophoretic profile of the normal peptided (N) and and…
Failure of anti-oxidant function results in the hydroxylation of an aromatic acid of Enzyme Z and its activation, so that it degrades protoporphyrin to porphyrin, an unstable product. When hit by light, this product further degrades to form a compound responsible for the lesions and excruciating pain the man suffers. The mutation also affected an amino acid at the N-terminal of Enzyme X. Sequencing of the first seven (7) amino acids at the N-terminal of the normal enzyme gave the following sequence: trp-arg-asp-leu-ser-gly-his When the cDNA was sequenced by the Sanger method utilizing ddCTP, the following products were obtained: Tetranucleotide Hexanucleotide Nonanucleotide Decanucleotide Dodenucleotide Octadecanucleotide Nonadecanucleotide 21-nucleotide The mutation involved the 19th bases of the template strand of the peptide. A comparison of the electrophoretic profile of the normal peptide (N) and mutant peptide (M) is shown below. The (+) electrode is situated at the bottom. pH…
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1/v 1/[S] Compound I is a substrate for the enzyme reverse transcriptase and compounds Il and lll are inhibitors. The inhibition plots for each compound are Illustrated above. The line labeled E is the enzyme with substrate alone (no inhibitor present). Answer the following questions by filling în the blanks. Line A most likely belongs to compound because it is a inhibitor. Line B belongs to compound because it is a inhibitor.