What will be the output of the following pseudo-code? Assume, head is a pointer to the first node of the following linked list. 5->2->8->2->9->2->11-> NULL Node *pres head; int count = 0; while(pres!= NULL && count < 3) { if(pres->key 2) { == count = count + 1; } pres = pres->next; } cout << pres->key « endl;

What will be the output of the following pseudo-code? Assume, head is a pointer to the first node of the following linked list. 5->2->8->2->9->2->11-> NULL Node *pres head; int count = 0; while(pres!= NULL && count < 3) { if(pres->key 2) { == count = count + 1; } pres = pres->next; } cout << pres->key « endl;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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