What will be the effects of each of the following changes in the reaction conditions in this experiment, assuming all other conditions remain the same. Explain your answers. a. increasing the amount of glacial acetic acid from 10 mL to 20 mL. b. increase the amount of nitric acid from 3.5 mL to 7.0 mL. c. decrease the amount of sulfuric acid from 1.5 mL to 5 mL.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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2. What will be the effects of each of the following changes in the reaction conditions in this experiment, assuming all other conditions remain the same. Explain your answers.
a. increasing the amount of glacial acetic acid from 10 mL to 20 mL.
b. increase the amount of nitric acid from 3.5 mL to 7.0 mL.
c. decrease the amount of sulfuric acid from 1.5 mL to 5 mL.
d. allow the temperature of the reaction mixture to remain at 40°C during the addition of the HNO3-H2SO4 solution.
3. Write chemical equations for the hydrolysis of p-nitroacetanilide in (a) aqueous acid; (b) aqueous hydroxide.
4. Predict what would happen during the recrystallization of p-nitroacetanilide in 95% ethanol if all of the acidic material had not been previously neutralized. Use an equation in your answer.

SYNTHESIS OF P-NITROACETANILIDE
H,SO,
NHCCH, + HNO,
O,N-
NHCCH, + H,O
CH,CO,H
nitric acid
(16 N)
acetanilide
p-nitroacetanilide
135.17
6.5 g
0.048
180.18
8.7 g (theory)
0.048 (theory)
MW:
63.02
weight:
moles:
3.5 mL
0.056
The mechanism of this reaction is as follows:
HO
OSH +
H0 + 0 N=
Transcribed Image Text:SYNTHESIS OF P-NITROACETANILIDE H,SO, NHCCH, + HNO, O,N- NHCCH, + H,O CH,CO,H nitric acid (16 N) acetanilide p-nitroacetanilide 135.17 6.5 g 0.048 180.18 8.7 g (theory) 0.048 (theory) MW: 63.02 weight: moles: 3.5 mL 0.056 The mechanism of this reaction is as follows: HO OSH + H0 + 0 N=
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