What will be displayed after the following code snippet is executed ? int] a = new int[O { 8, 3, 4, -2, 6 }; int t; for (int i = 0; i < 5; i++) { for (int j = 0; j < 4 - i; j++) { if (a[j] > a[j + 1])

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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What will be displayed after the following code snippet is executed ?
int] a = new int[] { 8, 3, 4, -2, 6};
int t;
for (int i = 0; i < 5; i++)
{
for (int j = 0; j < 4 - i; j++)
{
if (ai] > alj + 1])
{
t = ai];
a[j] = aj + 1];
alj + 1] = t;
}
}
}
for (int k = 0; k < 5; k++)
Console.Write("{O}\t", a[k]);
Transcribed Image Text:What will be displayed after the following code snippet is executed ? int] a = new int[] { 8, 3, 4, -2, 6}; int t; for (int i = 0; i < 5; i++) { for (int j = 0; j < 4 - i; j++) { if (ai] > alj + 1]) { t = ai]; a[j] = aj + 1]; alj + 1] = t; } } } for (int k = 0; k < 5; k++) Console.Write("{O}\t", a[k]);
Expert Solution
Explanation

Above code snippet does following things

  • Initialize integer array ={8,3, 4, -2, 6 } and declare int variable t
  • It sort the array a in ascending order such that elements will be arranged from smallest to largest.
  • This can be achieved through two loops.
    • The outer loop will select an element from array a
    • The inner loop allows us to compare selected element with rest of the elements.
    • It gets the smallest number at the first index
      • it uses variable t to swap smallest number at the first index
  • Above steps are repeated till all the numbes are arrange in ascending order
  • Finally another for loop displays sorted element of array  
    • -2 3 4 6 8

 

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