What type of BST traversal is corresponding to the code below?void Tree::Traverse(Node *node){if (node == NULL)| |Traverse(node->left);return;Traverse(node->right);cout << node->data << " ";}post-orderin-orderO pre-orderO None of them Given the below binary search tree, what are the nodes that will be evaluatedwhen searching for 0014?0010000500230003000800170026000700150019002400280013002500300010, 0005, 00080010, 0023, 0026, 00240010, 0023, 0017, 0015, 00130010, 0023, 0017, 0019

What type of BST traversal is corresponding to the code below? void Tree::Traverse(Node *node) { if (node == NULL) | | Traverse(node->left); return; Traverse(node->right); cout <« node->data << "' } O post-order O in-order O pre-order

What type of BST traversal is corresponding to the code below? void Tree::Traverse(Node *node) { if (node == NULL) | | Traverse(node->left); return; Traverse(node->right); cout <« node->data << "' } O post-order O in-order O pre-order

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };
Consider the following structure of a node for a linked list. struct Node { int key; Node *next; }; What will be the output of the following pseudo-code? Assume, head is a pointer to the first node of the following linked list. 5->2->8->2->9->2->11-> NULL Node *pres head; 0; while(pres!= NULL && Count key : int count 2) { count = count + 1; } pres = pres->next; } cout key « endl; 11 Error 2.
Subject is C++ programming
Question 1 The code below defines a singly-linked list. This consists of the following definition of node: 1 struct node { int val; struct node * next; 4 } Also, it uses the following insert function: struct node * insert(struct node * first, const int val) { 6 struct node * pred = NULL, * succ = first; 7 while (succ != NULL) { 8 if (succ->val val > val) 10 11 break; 12 succ = succ->next; 13 } struct node * this = malloc(sizeof (struct node)); this->val = val; 14 15 16 this->next = succ; 17 if (pred != NULL) { pred->next return first; } else { 18 this; %3D 19 20 21 return this; 22 } 23 } Note that the code above compiles correctly. (a) Give an implementation in C for a function that prints all values in the singly-linked starting from the first node and following the next node one by one along the list. Use the following signature: void print (struct node * first);
In this code: #include <iostream> #include <string> using namespace std;// Node struct to store data for each song in the playliststruct Node { string data; Node * next;};// Function to create a new node and return its addressNode * getNewNode(string song) { Node * newNode = new Node(); newNode -> data = song; newNode -> next = NULL; return newNode;}// Function to insert a new node at the head of the linked listvoid insertAtHead(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return;} newNode -> next = * head; * head = newNode;}// Function to insert a new node at the tail of the linked listvoid insertAtTail(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return; } Node * temp = * head; while (temp -> next != NULL) { temp = temp -> next; } temp -> next = newNode;}// Function to remove a node from the linked listvoid removeNode(Node ** head,…
what is the problem in the display function ? the code : #include <iostream>using namespace std; class node{public: int data; node* next;}; void display(node * head) // printing the data of the nodes{ node* temp = head; while (temp != NULL) { cout << temp->data << endl; temp = temp->next; }} // add void push(node** head, int newdata) // { 5, 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = *head; *head = newnode;} void append(node** head, int newdata) // { 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = NULL; node* last = *head; if (*head == NULL) { *head = newnode; return; } while (last->next != NULL) { last = last->next; } last->next = newnode;} void insertafter(node*…
Make an array of linked list for the following C code: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 = poly1->next;} // If power of…
Given the following C code: atruct Node int data: struct Node previ struct Node next: Which of the following statements deletes the node pointed by X? Assume that X points to the first node of linked list and head points to the head of linked list. a) X->prev-x->next; X->next-X->prev; b) Head-X->next; Head >prev-NULL; c) Head-X->prev; X->next-NULL; d) X->prev->prev - X->prev; X->next->next-X->next;
Create a function that uses Node * pointing to root of AVL Tree as an input and returns the height of the AVL tree in O(log(n)).