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- C1. Subject :- ChemistryAnswer the question below the reaction. H3C H3C H3C OH H3C In the second step of the reaction mechanism, which of the following is formed? CH3 CH3 CH3 + Excess NH4Cl CH3 CH3 CH3 CH3 H₂SO4 CH3 CI ха +H2OWhich of the following is NOT a rearrangement reaction? CH, CH, H,C CH, + CH3 H,C CH3 CH, CH, CH, CH, CH, H,C H,C + CH CH CH, CH, H,C H.
- Answer the question below the reaction. O4S H3C H3C H3C OH In the first step of the reaction mechanism, which of the following is formed? CH3 H3C CH3 CH3 + Excess NH4Cl OH CH3 (+) -OH2 CH 3 CH3 OH CH3 H₂SO₁ CH3 CI ха +H2O*** 4444 **** ***14 ****** 744444 250 ← → C 7 ✰ app.101edu.co Draw the major monobromination product of this reaction. 0 es Br2 (1 equiv) hv Draw Major Product C 1,502 JUN 30 Questio MacBookWhich side of this equilibrium is favored? Reactants because they are more stable Reactants because they are less stable Products because they are more stable Products because they are less stable
- QUESTION 2 Answer the question below the reaction. O + Excess NH4C1 +H₂O In the second step of the reaction mechanism, which of the following is formed? CH3 CI H₂C O CI H₂C O OH H₂C CH3 H₂C CH3 U 34 CH3 CH3 CH3 CH3 H₂SO4 CH3 CIWhich statement is false regarding the following system? + HX Addition Elimination H -X O A positive AG means that the equilibrium will favor the reactants because the entropy term is larger than the enthalpy term representing the gain of entropy when one molecule becomes two. O A negative AG means that the equilibrium will favor the products because the enthalpy term is larger than the entropy term representing the loss of entropy when two molecules become one. Elimination reactions are thermodynamically favored at high temperatures, where the entropy of the reaction will be larger than the enthalpy, causing a positive AG and the reactants to be favored over the products. Addition reactions are thermodynamically favored at high temperatures, where the entropy of the reaction will be larger than the enthalpy, causing a positive AG and the reactants to be favored over the products.10. Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction.
- Complete the given reactions. Add hydrogen atoms and charges to the appropriate atoms. Reaction A H₂C-CH₂-C -NCH, + NaOH H H₂C-CH₂-C-N-CH₂ + HCI H heat 2 heat Incorrect Reaction B OH Y H₂C 0 Na H₂N CH₂ H₂C OH H₂N CH₂|| C-H CH,OH Н-С-ОН Н-С -ОН Hydrogen catalyst НО -С —Н НО-С—Н H-C-OH Н-С—ОН H-C–OH Н-С-ОН CH,OH CH,OH Sorbitol GlucoseH3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3