A trucking company determined that the distance traveled per truck per year is normally distributed, with a mean of 80 thousand miles and a standard deviation of 12 thousand miles. Complete parts (a) through (d) below.a. What proportion of trucks can be expected to travel between 63 and 80 thousand miles in a year?The proportion of trucks that can be expected to travel between 63 and 80 thousand miles in a year is 0.4217.(Round to four decimal places as needed.)b. What percentage of trucks can be expected to travel either less than 70 or more than 95 thousand miles in a year?The percentage of trucks that can be expected to travel either less than 70 or more than 95 thousand miles in a year is 30.89 %.(Round to two decimal places as needed.)c. How many miles will be traveled by at least 90% of the trucks?The number of miles that will be traveled by at least 90% of the trucks is miles.(Round to the nearest mile as needed.)

Given data :Mean μ=80 thousand milesStandard deviation σ = 12 thousand miles.Let 'X' = the…

Answered: What proportion of trucks can be…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Samples of laboratory glass are in small, light packaging or heavy, large packaging. Suppose that 2% and 1% of the sample shipped in small and large packages, respectively, break during transit. If 59% of the samples are shipped in large packages and 41% are shipped in small packages, what proportion of samples break during shipment? Round your answer to four decimal places (e.g. 98.7654). Answer = Blank 1 Blank 1 Add your answer
1. Find the percentage of N.d. observations with a zz-score between z1= -3.04 and z2 = 2.85. Give your answer to two decimal places. 2. Find the proportion of N.d. observations with a zz-score between z1= -2.95 and z2 = 0.70. Give your answer to four decimal places.
Time left 0:4 From January to September, the mean number of car accidents per month was 630. From October to December, the mean was 1350 accidents per month. of The mean number of car accidents per month for the whole year was: a) 720 b) 675 c) 690 d) 810 e) 630
2. A customer at a specialty milk tea shop observed the amount of time, in minutes, that each of 20 customers spent waiting to receive an order. The results are recorded in the table below: Time (min) to receive order 3.2 4.0 3.8 2.4 4.7 5.1 4.6 3.5 3.5 6.2 3.5 4.9 4.5 5.0 2.8 3.5 2.2 3.9 5.3 Find the mean and sample standard deviation of these data. Interpret the results. 62 29 2.9
Suppose that we want to determine if the average amount of timespent online by the students is lessthan 4.5 hours/day. To this end, weconduct a survey of students and askthem how long they spend online perday. We obtain the following results:4.1, 4.3, 4.3, 4.5, 4.6, 4.3, 4.1, 4.6,4.7, 4.6, 4.7, 4.1, 4.3, 4.3, 4.5, 4.6,4.3, 4.1, 4.6, 4.7, 4.6, 4.7, 4.5, 4.6,4.3, 4.1 Assume that the number ofhours spent online has a normal distribution. Test your hypot
4.2
Statistics Question
Find the LU factorization of and use it to solve the system A = -4 16 10 -2 -2 2 -2 2 -3 6 -9 -5 -7 X2 10-0 -4 -7 -10 -22 2 6 -9 -5 -7 -4 16 1 -4 10 -7 -10 -22 A = LU 4 = -13 32 -14
5.) 35 students were enrolled on the first day of a English class. By mid-semester, there were only 20 students left. What was the percentage decrease in enrolled students from the first day of class to the mid semester? Round your answer to one decimal place.
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.Santa Fe black-on-white is a type of pottery commonly found at archaeological excavations at a certain monument. At one excavation site a sample of 580 potsherds was found, of which 370 were identified as Santa Fe black-on-white. (a) Let p represent the proportion of Santa Fe black-on-white potsherds at the excavation site. Find a point estimate for p. (Round your answer to four decimal places.)(b) Find a 95% confidence interval for p. (Round your answers to three decimal places.) lower limit upper limit
Suppose the lengths of human pregnancies are normally distributed with µ = 266 days and o= 16 days. Complete parts (a) and (b) below. (Type integers or decimals.) A. The proportion of human pregnancies that last less than B. The proportion of human pregnancies that last more than days is days is Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts less than B. The probability that a randomly selected human pregnancy lasts more than (b) The figure to the right represents the normal curve with µ = 266 days and o = 16 days. The area between x = 280 and x = 295 is 0.1558. Provide two interpretations of this area. days is days is Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or…
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