What is wrong with this “proof”? “Theorem” For every positive integer n, if x and y are positive integers with max(x, y) = n, then x = y. Basis Step: Suppose that n = 1. If max(x, y) = 1 and x and y are positive integers, we have x = 1 and y = 1. Inductive Step: Let k be a positive integer. Assume that whenever max(x, y) = k and x and y are positive integers, then x = y. Now let max(x, y) = k + 1, where x and y are positive integers. Then max(x − 1, y − 1) = k, so by the inductive hypothesis, x − 1 = y − 1. It follows that x = y, completing the inductive step.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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What is wrong with this “proof”?
Theorem” For every positive integer n, if x and y are positive integers with max(x, y) = n, then x = y.
Basis Step: Suppose that n = 1. If max(x, y) = 1 and x and y are positive integers, we have x = 1 and y = 1.
Inductive Step: Let k be a positive integer. Assume that whenever max(x, y) = k and x and y are positive integers, then x = y. Now let max(x, y) = k + 1, where x and y are positive integers. Then max(x − 1, y − 1) = k, so by the inductive hypothesis, x − 1 = y − 1. It follows that x = y, completing the inductive step.

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