Answers to 4.5.2 Solving Polynomials: Irational Conjugates 1) 1- V7, 2-2vi 2) -3 - Vi, 3- VE 5) flz) =x + 12r+42x + 36x + 8 7) sla) =x* + 4x + 2r- 4x +1 9) flz) =x* - 6x +9 3) -3- V7, 1- V5 4) -3- V6 6) flz) =x - 16x+64 8) (x) =x - 14x² + 49 10) flz) =x* - 2r – 26x + 2r +1

Q: Time le If it is given that -2- 3i is one of the roots of the polynomial z3 + 9z2 + pz + 65 = 0,…

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Q: Can someone answer all of these polynomials?

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Q: Factor the polynomial completely. 22) 125x³+y3 A) (125x + y)(x2 - 5xy + y2) C) (5x - y) (25x2 + 5xy…

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Q: Determine the roots algebraically by fact a) x- 8x2- 3x + 90 = 0 b) x + 9x + 21x - x - 30 = 0 c)…

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Q: Three rational expressions have the following characteristics: a) Rational Expression 1 i. NPV's=…

A: Given that  a) NPV's are 52 and -5 and numerator is a difference of squares polynomial. b) NPV's are…

Q: Which quadratic has zeroes of 5 and 5/2  A) (q + 5)(5q + 2) B) (q - 5)(2q - 5) C) (q - 5)(5q - 2)…

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Q: The positive value of k for which x2+kx+64=0 & x2-8x+k=0 will have real roots

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Q: Polynomial P(x)=9x100-5x7-2x2-4 is divided by (x+1). Find the remainder.

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Q: Exit Ho 9289 6/2377 Standard Form: Synthetic Division: 4.) (8x³ +36x² + 11x-20) = (x+4) X-4 5.) Find…

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Q: b) f(x) = x* + 29x² + 100.

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Q: If fx)x3x+1 then fx) (In x]3x (3x+1}x3x (2x+ In xr3x+ 1 3x13r 3 Inx 3x+13 In x

A: Note:Hi there! Thank you for posting the question. The first line in the image is not very clear.…

Q: m) x -8x Quadratics of the Form ax? + bx + Decomposition or 12x-5x-2=12x-8x +3x-2 = 4x(3x-2)+1(3x-2)…

A: Given that  To solve the equations into quadratic form

Q: (3w ^ 3 + 7w ^ 2 - 4w + 3) / (w + 3) divide polynomials

A: Explanation and solution is given below....

Q: 6. Factor each polynomial using the factor theorem.1 3- 3x2. 10x + 24 d) 4x* + 7x e) x - 5x – 7x³ +…

A: We find out the factors of the given polynomials.

Q: Divide. 1) (10n - 26n? + 92n – 48) + (10n – 6) 2) (90v + 9v3 - 27 - 72v2) + (9v – 9) 3) (8x* - x -…

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Q: '-7r + 19r- 13 and write it as the product of three 2. (3.4) Factor the polynomial P(r)-r linear…

A: Substitute x=1 in the given equation Then P(x)=0 So (x-1) is a factor of P(x)