Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
What is the total number of oxygen atoms on the right-hand side of this chemical equation?
**Chemical Equation:**
\[ 3 \text{HNO}_2(aq) \rightarrow \text{HNO}_3(aq) + \text{H}_2\text{O}(l) + 2\text{NO}(g) \]
**Instructions:**
- Calculate the total number of oxygen atoms in the products on the right-hand side.
- Enter the number in the provided text box.
- Use the "X" button to clear your answer or the "refresh" button to reset the question.
**Explanation:**
On the right-hand side of the equation:
- \(\text{HNO}_3(aq)\) has 3 oxygen atoms.
- \(\text{H}_2\text{O}(l)\) has 1 oxygen atom.
- \(2\text{NO}(g)\) has 2 molecules of NO, each with 1 oxygen atom, totaling 2 oxygen atoms.
**Total Calculation:**
3 (from \(\text{HNO}_3\)) + 1 (from \(\text{H}_2\text{O}\)) + 2 (from \(2\text{NO}\)) = **6 oxygen atoms**
Place your answer, "6," in the text box provided.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d5797ed-cea5-4b70-8db3-2ef7e3018a4a%2F5c8e1838-18fc-4f94-854d-d50a7e9299ce%2Fpxtmh0v_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
What is the total number of oxygen atoms on the right-hand side of this chemical equation?
**Chemical Equation:**
\[ 3 \text{HNO}_2(aq) \rightarrow \text{HNO}_3(aq) + \text{H}_2\text{O}(l) + 2\text{NO}(g) \]
**Instructions:**
- Calculate the total number of oxygen atoms in the products on the right-hand side.
- Enter the number in the provided text box.
- Use the "X" button to clear your answer or the "refresh" button to reset the question.
**Explanation:**
On the right-hand side of the equation:
- \(\text{HNO}_3(aq)\) has 3 oxygen atoms.
- \(\text{H}_2\text{O}(l)\) has 1 oxygen atom.
- \(2\text{NO}(g)\) has 2 molecules of NO, each with 1 oxygen atom, totaling 2 oxygen atoms.
**Total Calculation:**
3 (from \(\text{HNO}_3\)) + 1 (from \(\text{H}_2\text{O}\)) + 2 (from \(2\text{NO}\)) = **6 oxygen atoms**
Place your answer, "6," in the text box provided.
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