Potassium perchlorate is prepared by the following sequence of reactions: Cl₂ (g) + 2 KOH(aq) → KCl(aq) + KClO(aq) + H₂O(l) 3 KClO(aq) → 2 KCl(aq) + KClO3(aq) 4 KClO3(aq) → 3 KClO4 (aq) + KCl(aq) What mass of Cl₂ (g) is required to produce 165 kg of KC1O4? Mass= g

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter6: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 111AE
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**Title: Preparation of Potassium Perchlorate**

**Introduction:**
Potassium perchlorate (KClO₄) is a chemical compound commonly used in various applications, including pyrotechnics and as an oxidizing agent in laboratory settings. It can be prepared through a sequence of chemical reactions involving chlorine gas (Cl₂), potassium hydroxide (KOH), and potassium chloride (KClO₃).

**Chemical Reactions:**

1. **First Reaction:**
   \[ \text{Cl}_2(g) + 2 \text{KOH}(aq) \rightarrow \text{KCl}(aq) + \text{KClO}(aq) + \text{H}_2\text{O}(\ell) \]

2. **Second Reaction:**
   \[ 3 \text{KClO}(aq) \rightarrow 2 \text{KCl}(aq) + \text{KClO}_3(aq) \]

3. **Third Reaction:**
   \[ 4 \text{KClO}_3(aq) \rightarrow 3 \text{KClO}_4(aq) + \text{KCl}(aq) \]

**Problem Statement:**
Determine the mass of chlorine gas (Cl₂) required to produce 165 kg of potassium perchlorate (KClO₄).

**Calculation:**

\[ \text{Mass} = \_\_\_\_\_\_\_ \text{g} \]
Transcribed Image Text:**Title: Preparation of Potassium Perchlorate** **Introduction:** Potassium perchlorate (KClO₄) is a chemical compound commonly used in various applications, including pyrotechnics and as an oxidizing agent in laboratory settings. It can be prepared through a sequence of chemical reactions involving chlorine gas (Cl₂), potassium hydroxide (KOH), and potassium chloride (KClO₃). **Chemical Reactions:** 1. **First Reaction:** \[ \text{Cl}_2(g) + 2 \text{KOH}(aq) \rightarrow \text{KCl}(aq) + \text{KClO}(aq) + \text{H}_2\text{O}(\ell) \] 2. **Second Reaction:** \[ 3 \text{KClO}(aq) \rightarrow 2 \text{KCl}(aq) + \text{KClO}_3(aq) \] 3. **Third Reaction:** \[ 4 \text{KClO}_3(aq) \rightarrow 3 \text{KClO}_4(aq) + \text{KCl}(aq) \] **Problem Statement:** Determine the mass of chlorine gas (Cl₂) required to produce 165 kg of potassium perchlorate (KClO₄). **Calculation:** \[ \text{Mass} = \_\_\_\_\_\_\_ \text{g} \]
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