What is the specific heat of a substance if 120 kJ of heat is needed to raise 4.1 kg of the substance from 18 degrees Celsius to 37.2 degrees Celsius?
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What is the specific heat of a substance if 120 kJ of heat is needed to raise 4.1 kg of the substance from 18 degrees Celsius to 37.2 degrees Celsius?
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- The mass of a hot-air balloon and its cargo (not including the air inside) is 200 kg. The air outside is at 10.0C and 101 kPa. The volume of the balloon is 400 m3. To what temperature must the air in the balloon be warmed before the balloon will lift off? (Air density at 10.0C is 1.244 kg/m3.)At 25.0 m below the surface of the sea, where the temperature is 5.00C, a diver exhales an air bubble having a volume of 1.00 cm3. If the surface temperature of the sea is 20.0C, what is the volume of the bubble just before it breaks the surface?Convert the following to equivalent temperatures on the Celsius and Kelvin scales: (a) the normal human body temperature, 98.6F; (b) the air temperature on a cold day, 5.00F.
- A ceramic container used for melting metals (called a crucible) contains 1.30 kg of a molten metal. The liquid metal cools until it reaches its melting point of 1,749°C. A scientist then measures that 2.99 ✕ 104 J of heat is transferred out of the metal before it completely solidifies. What is the latent heat of fusion of this metal, in J/g? (Be careful with units!)If 31.0 g of milk at a temperature of 4.15°C is added to a 250-g cup of coffee at a temperature 91.0°C, what is the final temperature of the mixture? Assume coffee has a specific heat of 4.19 ✕ 103 J/(kg · K) and milk has a specific heat of 3.93 ✕ 103 J/(kg · K).A 100 g glass container contains 250 g of water at 15.0 "C. A 70 g piece of unknown material at 100 °C is added to the water in the container. The final temperature of the mixture is 19.0 °C. What is the specific heat of the unknown material in J/kg "C? (specific heat of water = 4,186 J/kg "C, specific heat of glass=837.2 J/kg "C)
- How much heat would flow into an 80 cm x 40 cm x 3.0 mm glass window each hour on a day when the outside temperature is 103 F and inside temperature is 70 F? Kglass = 0.84 W/m-K. O 1.64x10³ J/s O 2.96x10² J/s O 1.64x10² J/s O 2.96x10³ J/sOn a cold winter morning you step outside to get into your car and drive to work. Your car's windshield is covered with ice at −14.3°C. If the area of the windshield is 1.40 m2 and it takes 1.77 105 J of heat to melt the ice, how thick was the ice covering the windshield? The latent heat of fusion of ice is 334 kJ/kg, the specific heat of ice is 2092 J/(kg · °C) and its density is 917 kg/m3 (answer in m).On a cold winter morning you step outside to get into your car and drive to work. Your car's windshield is covered with ice at −15.3°C. If the area of the windshield is 1.40 m2 and it takes 1.97 105 J of heat to melt the ice, how thick was the ice covering the windshield? The latent heat of fusion of ice is 334 kJ/kg, the specific heat of ice is 2092 J/(kg · °C) and its density is 917 kg/m3.
- Specific Heat of Water = 4186 J/kg °C, Specific Heat of Iron = 452 J /kg °C, Specific Heat of Ice = 2093 J/kg °C, Specific Heat of Lead = 130 J/kg °C Latent Heat of Fusion = 3.34 x 105 J/kg, Specific Heat of Copper = 385.1 J /kg.°C Density of iron = 7.874 g /cm3 Density of copper = 8.95 g /cm3 2. Convert 403 K to °F temperature.Problem 4. (a) How much heat transfer is necessary to raise the temperature of 0.800kg of water from 0°C to 30.0°C? (b) How much heat transfer is required to first melt 0.800kg of 0°C ice and then raise its temperature to 30.0°C? Hint: Look up the specific heat and heat of fusion of water.If the specific heat of water is 4,186 J/kg∙°C, how much heat is required to increase the temperature of 1.2 kg of water from 23 °C to 39 °C?. Hint: To get the ΔT (Change in temperature), get the difference between final temperature (Tf) and initial temperature (Ti). [ΔT = Tf – Ti ]
