what is the Physicists recognize four fundamental forces. * - Flectrical force - Gravitational force Strong nuclear force - Weak nuclear force Muscular force Force of friction Ff is described by • Ff = µN O u synovlal fluld in the joints u coefficient of fraction between two surface in The temperature of the human body is normally about 98.6 F.calculate the temperature of the body °C oC = (5/9)x(oF-32) =5/9(98.6- 32)-37 oC oc=(9/5)x(of -32) =9/5(98,6-32) =13,3

what is the Physicists recognize four fundamental forces. * - Flectrical force - Gravitational force Strong nuclear force - Weak nuclear force Muscular force Force of friction Ff is described by • Ff = µN O u synovlal fluld in the joints u coefficient of fraction between two surface in The temperature of the human body is normally about 98.6 F.calculate the temperature of the body °C oC = (5/9)x(oF-32) =5/9(98.6- 32)-37 oC oc=(9/5)x(of -32) =9/5(98,6-32) =13,3

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter1: Basic Modes Of Heat Transfer

Section: Chapter Questions

Problem 1.77P: 1.77 Explain each in your own words. (a) What is the mode of heat transfer through a large steel...

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1.22 In order to prevent frostbite to skiers on chair lifts, the weather report at most ski areas gives both an air temperature and the wind-chill temperature. The air temperature is measured with a thermometer that is not affected by the wind. However, the rate of heat loss from the skier increases with wind velocity, and the wind-chill temperature is the temperature that would result in the same rate of heat loss in still air as occurs at the measured air temperature with the existing wind. Suppose that the inner temperature of a 3-mm-thick layer of skin with a thermal conductivity of 0.35 W/m K is and the air temperature is . Under calm ambient conditions the heat transfer coefficient at the outer skin surface is about (see Table 1.4), but in a 40-mph wind it increases to . (a) If frostbite occurs when the skin temperature drops to about , do you advise the skier to wear a face mask? (b) What is the skin temperature drop due to the wind?
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The left side of this equation tells how much energy Q the cylinder gives to the water while it cools. The right side of this equation tells how much energy Q the water and aluminum cup absorb from the cylinder to warm up. Because it is the same energy, they are equal. What is known in this equation? Mcyl 411.7 g, malum 46.5 g, malum+water = 175 g Can you find: mwater =? g Twater = Talum = 20°C (water and cup of room temperature) 90°C, T; = 35°C (hot cylinder and cool "cylinder+cup+water" temperatures) Tcyl kCal Calum = 0.22, Cwater 1 (specific heat of water and aluminum, measured in units kg-°C What are we looking for is Ccul - How we find it? Plug all the numbers into the equation (1), Ccul will be one unknown which you can calculate from the equation. Important, convert all the masses from grams to kilograms! After you find Ccyl, compare it to known value for the copper 0.093(our cylinder is made out of copper). |Ceyl -0.093| % : · 100% 0.093
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