**Titration Calculation Example****Question:**What is the pH when Jeremiah has added 18.0 mL of 0.275 M NaOH to 20.0 mL of 0.500 M HClO₃?**Chemical Equation:**HClO₃ + NaOH → NaClO₃ + H₂O**Calculation:**pH = [?]---**Explanation:**Let's break down the information provided and solve for the pH step-by-step:1. Understand the reaction: An aqueous solution of strong acid HClO₃ is reacting with a strong base NaOH.2. Calculate the moles: - Moles of HClO₃ (Weak Acid): Molarity × Volume = 0.500 M × 20.0 mL/1000 mL = 0.0100 moles - Moles of NaOH (Strong Base): Molarity × Volume = 0.275 M × 18.0 mL/1000 mL = 0.00495 moles3. Determine the reaction's completion: - Since we are adding fewer moles of NaOH than HClO₃, the base will be the limiting reagent, and the reaction will proceed until all NaOH is consumed. - Moles of HClO₃ remaining after the reaction = Initial moles of HClO₃ - Moles of NaOH added = 0.0100 moles - 0.00495 moles = 0.00505 moles4. Calculate the concentration of the remaining HClO₃ in the final mixture: - Total volume of the mixture = 20.0 mL HClO₃ + 18.0 mL NaOH = 38.0 mL = 0.038 L - Concentration of HClO₃ = Moles / Volume = 0.00505 moles / 0.038 L ≈ 0.13289 M5. Finally, determine the pH. Since HClO₃ is a strong acid, pH ≈ -log[H⁺] - [H⁺] = Concentration of HClO₃ = 0.13289 M - pH = -log(0.13289) ≈

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Answered: What is the pH when Jeremiah has added…

What is the pH when Jeremiah has added 18.0 mL of 0.275 M NaOH to 20.0 mL of 0.500 M HCIO3? HCIO3 + NaOH → NaCIO3 + H₂O pH = [?] pH at 18.0 mL base Enter

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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