What is the output of the code fragment given below? int i; int j = 0; %3D for (i = 0; i <= 6; i++) { %3D if (i 8 2 == 0) { i = i + 2; j++; }
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- int f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?What does the function f do? struct Point2D { double x; double y; struct Triangle { Point2D v1; Point2D v2; Point2D v3; }; void f(Triangle&t) { } int temp = 12.5; temp = t.v1.x; t.v1.x = t.v1.y; t.v1.y = temp; } int main () { Triangle mytri; mytri.v1.x = 1.0; mytri.v1.y = 22.5; f (mytri); Swaps values of x and y in vertex 1 of an argument of type Triangle Initializes value of x in vertex 1 of an argument of type Triangle Sets all x,y values in all vertices of an argument of type Triangle Swaps value of x in vertex 1 with value of x in vertex 2, for an argument of typeFor the C++ program show on the next page, answer the questions that follow. The names g, j, x, and y are declared multiple times. Distinguish uses of these names using line numbers where they were declared as subscripts. a. At point A in the program, what names are in scope? b. At point A in the program, what variables are live? c. At point B in the program, what names are in scope? d. At point B in the program, what variables are live?
- 3: The code on the right is supposed to be the ARM code for procA; however, there are problems with the ARM code. C code: int procA(int x, int y) { int perimeter = (x + y) * 2; I return perimeter; } ARM code: I procA: add rø, r1, r2 mov r1, rø lsl #1 bx lr push {lr} Give the corrected version of the ARM code for procA:for (int i = 1; i <= 3; i++) { for (int j = 1; j <= 3; j++) { System.out.print((i * j) + " "); }#include<stdio.h> #include<stdarg.h> void fun1(int num, ...); void fun2(int num, ...); int main() { fun1(1, "Apple", "Boys", "Cats", "Dogs"); fun2(2, 12, 13, 14); return 0; } void fun1(int num, ...) { char *str; va_list ptr; va_start(ptr, num); str = va_arg(ptr, char *); printf("%s ", str); } void fun2(int num, ...) { va_list ptr; va_start(ptr, num); num = va_arg(ptr, int); printf("%d", num); }.
- void main (void) { char result = a; for (char i = { 10; i > 5; i = i-1) result = result + i; } // point B } Consider the code above. What is the decimal value of "result" at "point B" if the variable "a" is initially 59?int x1 = 66; int y1 = 39; int d; _asm { } mov EAX, X1; mov EBX, y1; push EAX; push EBX; pop ECX mov d, ECX; What is d in decimal format?In java there must be at least two calls to the function with different arguments and the output must clearly show the task being performed. 1. Develop a function that accepts an array and returns true if the array contains any duplicate values or false if none of the values are repeated. 2. Develop a function that returns true if the elements are in decreasing order and false otherwise. 3. A "peak" is a value in an array that is preceded and followed by a strictly lower value. For example, in the array {2, 12, 9, 8, 5, 7, 3, 9} the values 12 and 7 are peaks. Develop a function that returns the number of peaks in an array of integers. Note that the first element does not have a preceding element and the last element is not followed by anything, so neither the first nor last elements can be peaks. 4. Develop a function that finds the starting index of the longest subsequence of values that is strictly increasing. For example, given the array {12, 3, 7, 5, 9, 8, 1, 4, 6}, the function…
- Х3: inlTol0 Write a function in Java that implements the following logic: Given a number n, return true if n is in the range 1..10, inclusive. Unless "outsideMode" is true, in which case return true if the number is less or equal to 1, or greater or equal to 10. Your Answer: 1 public boolean in1To10(int n, boolean outsideMode) 2 { 3 } H N Mplease code in java and dont use advanced coding.. keep it basicQuestion #4: Re-write the program of Question #3 using data files. The input data numbers.txt contains (positive) integer numbers. Each time the program reads a number, check whether it is a prime and stores the result in the output file Results.txt. 373 373 is Prime!! 11 11 is Prime!! 2552 is NOT prime!! 5 is Prime!! 3561 is NOT prime!! 2552 3561 numbers.txt Results.txt