QuestionWhat is the order of growth of the worst-case running time ofthe following code fragment as a function of n?int sum = 0;for (int ifor (int j1; i <= n; i++)1; ji*i; j++)く=sum++;AnswerMark the best answer.01'log nOn^(1/2)n log nOn^(3/2)n^2n^2 log nn^(5/2)On^3On^4n^5On^6On^7 QuestionGive the parent [] array that results from the following sequence of 9 unionoperations on a set of 10 items using the weighted quick-union algorithm from lecture.9-02-49-38-56-34-86-14-08-7Recall: when joining two trees of equal size, our weighted quick-union convention is tomake the root of the second tree point to the root of the first tree. Also, our weightedquick-union algorithm performs union by size (number of nodes) -and does not do path compression.not union by heightAnswerYour answer should be a sequence of 10 integers (between 0 and 9), separated by whitespace.

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Computer Science Convert this sequential code into parallel C code. Given constants aj and bk stored in arrays a[ [ ] and b[ ], respectively, and values for unknowns to be stored in array, x[ ], sequential code could be x[0] = b[0]/a[0][0]; * computed separately */ *for remaining unknowns*/ %3D for (i = 1; i< n; i++) { sum = 0; For (j = 0; j< i; j++ sum = sum + a[i][j]*x[j]; %3D %3D x[i] = (b[i] - sum)/a[i][i]; }
bool isprime(long n) /* fixed from to https://www.geeksforgeeks.org/euclid-euler-theorem/?ref=lbp */{ // check whether a number is prime or not int i; for (i = 2; i * i <= n; i++) if (n % i == 0) return false; return true;}
What are the complexities of the following code segments in terms of n? Give an upper bound. a) int i=1;while (i<= n) { int j = i; while (j > 0) j = j/2;i++; } b) int i,j s=0; for (i=0; i<n; i++) { i--; s++; if (s == n) { i++; s = 0; } } c) while (n > 0) { for (int i=0; i<n; i++) sum++; n = n/2; }
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What is the order of growth of the worst-case running time of the following code fragment as a function of n? int sum = 0; for (int i = 1; i <= n; i++) for (int j = 1; j <= i*i; j++) %3D sum++;