void find_and replace (char A, char olde, char *newc) for (int i=0; i<5; i++) for (int j-0; j<3; j++) oldcljl) A[i] = newc[j]; if (A[i] The procedure is tested with the following four test cases. 1. oldc = "abc", newc 2. oldc = "cde", newc "bca", "abc" , newc "dab" "bcd" "cda" "bac" 3. oldc 66 newc 4. olde

void find_and replace (char A, char olde, char *newc) for (int i=0; i<5; i++) for (int j-0; j<3; j++) oldcljl) A[i] = newc[j]; if (A[i] The procedure is tested with the following four test cases. 1. oldc = "abc", newc 2. oldc = "cde", newc "bca", "abc" , newc "dab" "bcd" "cda" "bac" 3. oldc 66 newc 4. olde

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include <iostream>using namespace std;class test{public:test(){cout<<"alpha\n";}~test(){cout<<"beta\n";}};int main(int argc, char const *argv[]){test *a = new test[5];delete[] a;return 0;} Give output.
#include <iostream>using namespace std;class test{public:test(){cout<<"alpha\n";}~test(){cout<<"beta\n";}};int main(int argc, char const *argv[]){test *a = new test[5];delete[] a;return 0;} Give output.
۱٪۹۳ 14 A + } What is the output of the following codes int arr[10] = {2,7,5,2,7,9,4,5,2,3}; int count[10] = {0}; for (int i = 0; i < 10; i++){ ++count[arr[i]]; } for (int i = 0; i < 10; i++){ if (count[i] == 1) ●●● printf("%d", i); Full O. A. ٨:٥٣ م السبت ٢٩ أكتوبر 349
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#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…
// add.ll define void @add(i32* %ptr1, i32* %ptr2, i32* %val) {ret void} Fill add.ll function to do the following operation: void add(int *ptr1, int *ptr2, int *val) { *ptr1 += *val; *ptr2 += *val; } This is the full question. It is related to LLVM. If it's going to help there is one more code given which is: #include <stdio.h> void add(int *ptr1, int *ptr2, int *val); int main(int argc, char **argv) {FILE *f = fopen(argv[1], "r");int a, b, c;fscanf(f, "%d %d %d", &a, &b, &c);add(&a, &b, &c);printf("%d %d\n", a, b);fclose(f); return 0;}
#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…
What happens when the ref or out keyword is used with an array parameter?
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