6. What is the orbital velocity of Reva as he circles theearth at a height of 3000 km above the surface? (Themass of the Earth is approximately 5.98 x 104 kg, andits radius is 6.38 x 10° m.) G = 6.67 x 10"Nm³/kg(4 marks)

Gravitation force is a force between two bodies that arises due to the virtue of their masses. The…

Answered: What is the orbital velocity of Reva as…

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

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A 1000 kg satellite orbits the Earth at a distance of 4 times the Earth's radius measured from above the Earth's surface. The radius of the Earth is 6.38x 10°m and the mass of the Earth is 5.98x1024kg and the gravitational constant G= 6.67x10-11 Nm²/kg². What is the speed at which the satellite orbits the earth? 3540 m/s O 3780 m/s O 4110 m/s 3130 m/s 2920 m/s O 4370 m/s 3960 m/s O 3350 m/s
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Consider the gravitational acceleration on the surface of the Moon and of Mars. a) What is the acceleration, in meters per square second, due to gravity on the surface of the Moon? You will need to look up the mass and radius of the Moon. b) What is the acceleration, in meters per square second, due to gravity on the surface of Mars? The mass of Mars is 6.418 × 1023 kg and its radius is 3.38 × 106 m. Given: the radius of the moon is 1,080 miles
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A satellite is traveling around a planet in a circular orbit with radius R. It moves in a constant speed of v = 1.02 × 104 m/s. The mass of the planet is M = 5.94 × 1024 kg. The mass of the satellite is m = 4.7 × 103 kg. Enter an expression for the magnitude of the gravitional force F in terms of M,R,m and the gravitional constant G. Enter an expression for the radius in terms of G,M and R. Enter an expression for the gravational potetial energy PE in terms of G,M,m and R. Enter an expresssion for the centripal acceleration of the satellite ac in terms of the speed of the satellite v, and r.
The earth orbits the sun once per year (365 days) and its average orbital radius is 1.50 x 1011m. The mass of the sun estimated from this data and Kepler’s Third “Law” is? T2=(4π2/Gmsun)r3 G=6.67 x 1011Nm2/kg2
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Could I please have some guidance on the steps for this? An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic orbit. If the distance from the center of the moon to the surface of the planet is 2.450×105 km and the planet has a radius of 3.850×103 km and a mass of 4.90×1022 kg , how long (in days) does it take the moon to make one revolution around the planet? The gravitational constant is 6.67×10−11N·m2/kg2.
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What is the orbital velocity of Reva as he circles the earth at a height of 3000 km above the surface? (The mass of the Earth is approximately 5.98 x 10* kg, and its radius is 6.38 x 10° m.) G = 6.67 x 10"Nm²/kg²