A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet? [Given: Mass of planet = 8 x 1022 2 kg Radius of planet = 2 x 106 m Gravitational constant, G = 6.67 x 1011 Nm2/kg²] %3D

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Chapter1: Units, Trigonometry. And Vectors
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A spaceship orbits around a planet at a height
of 20 km from its surface. Assuming that only
gravitational field of the planet acts on the
spaceship, what will be the number of
complete revolutions made by the spaceship
in 24 hours around the planet?
[Given: Mass of planet = 8 x 1022
2 kg
Radius of planet = 2 x 106 m
Gravitational constant, G = 6.67 x 1011
Nm2/kg²]
%3D
Transcribed Image Text:A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet? [Given: Mass of planet = 8 x 1022 2 kg Radius of planet = 2 x 106 m Gravitational constant, G = 6.67 x 1011 Nm2/kg²] %3D
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