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What is the N of an solution if 45.23 mL of it is required to titrate a 0.2505 sample of Na2CO3 ?

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter3: Statistical Tests With Excel

Section: Chapter Questions

Problem 1P

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Question

3. What is the N of an solution if 45.23 mL of it is required to titrate a 0.2505 sample of Na2CO3 ?

MODULE 8 ACTIVITY 2 INDIVIDUAL ACTIVITY
ΟΝ ΑΝACHEM LEC
PROBLEMS ON VOLUMETRIC ANALYSIS
Instruction: After studying the ppt on Volumetric
Analysis and Module 8 answer the ff problems.
Use the following formula:
1. C,V1
3. %analyte =Nitrant X_Vitrant X_ EqWt Analyte x 100%
C,V2
'acid X V
acid
Nbase
X V,
base
wt. of sample
Problems:
1. What volume of 0.2963 N H,SO, is required to prepare
250. 0 mL of 0.1000 N H,SO,?
2. What is the N of an HCl solution if 25.03 mL of it
requires 29.07 mL of 0.1025 N NAOH for titration?
3. What is the N of an HCl solution if 45.23 mL of it is
required to titrate a 0.2505 sample of Na,CO;?
4. A sample of soda ash (impure Na,CO;) is titrated with
0.5000 N H,SO. If the sample weighs 1.1000 g and
requires 35.00 mL of the acid for complete neutralization,
what is the %Na,CO, in the ash assuming no other active
component is present?
4•
At. Mass: C 35.45
O 16.00
Ag 107.9
Mg 24.31
30.97
Fe 55.85
Al 26.98
Na 22.99
С 12.01
Volumetric Analysis . Show your solution in the
appropriate box. For each problem, give the derived
formula, substitute the given in the formula and write
the final answer on the last column with proper unit &
correct no. of SF.
Derived Formula Substitute the given in the formula Final answer
1.
2.
3.

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