Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What volume (L) of 0.236 M potassium hydroxide solution would just neutralize 49.3 mL of 0.217 M H2SO4 solution?
Expert Solution

Step 1
The reaction between H2SO4 and KOH is given as
H2SO4 + 2 KOH ---> K2SO4 + 2 H2O
Hence from the above balanced reaction we can say that the moles of KOH required = moles of H2SO4 to be neutralised X 2
Since moles of H2SO4 to be neutralised = molarity of H2SO4 solution X volume of H2SO4 solution in L = 0.217 X 49.3 / 1000
=>moles of H2SO4 to be neutralised = 0.0107 approx
hence moles of KOH required = 0.0107 X 2 = 0.0214
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