What is the maximum mass of S8 that can be produced by combining 93.0 g of each reactant? 8SO2+16H2S⟶3S8+16H2O STRATEGY: Convert 93.0 g SO2 to moles, then find the corresponding amount of S8. Convert 93.0 g H2S to moles, then find the corresponding amount of S8. Identify the limiting reactant and calculate the mass of S8 produced. Step 1: 93.0 g SO2 and excess H2S produce 0.544 mol S8. Step 2: 93.0 g H2S and excess SO2 produce 0.512 mol. Step 3: When 93.0 g SO2 and 93.0 g H2S are mixed, how much S8 forms? How much S8 forms? -0.544 mol S8 -0.544+0.512 mol S8 -0.512 mol S8   which is equal to: _________ g S8

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".