In the reaction of 28 g NO2and 18 g H2O by the chemical equation: NO2 (g) + H2O (1)→HNO; (1) + NO (g) a- Balanced the reaction equation. b- Calculate the moles of given reactants. c- Calculate the moles of product, HNO3. Solve it on a sheet d- Calculate the mass of HNO3 formed in grams. e- Which of the reactants is the limiting reagent? N=14g/ mol, O = 16g/mol,H=1 gmol. www

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In the reaction of 28 g NO2and 18 g H2O by the chemical equation:
NO2 (g) + H2O (1) → HNO3 (1) + N0 (g)
a- Balanced the reaction equation. b- Calculate the moles of given reactants.
c- Calculate the moles of product, HNO3. Solve it on a sheet
d- Calculate the mass of HNO3 formed in grams.
e- Which of the reactants is the limiting reagent? N=14g/ mol. O = 16g/mol,H=1 gmol.
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Transcribed Image Text:In the reaction of 28 g NO2and 18 g H2O by the chemical equation: NO2 (g) + H2O (1) → HNO3 (1) + N0 (g) a- Balanced the reaction equation. b- Calculate the moles of given reactants. c- Calculate the moles of product, HNO3. Solve it on a sheet d- Calculate the mass of HNO3 formed in grams. e- Which of the reactants is the limiting reagent? N=14g/ mol. O = 16g/mol,H=1 gmol. wwww
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