**Problem Statement:**How many grams of KBrO₃, with a molar mass of 167.0 g/mol, are required to prepare 0.828 moles of Br₂ according to the balanced reaction?**Chemical Reaction:**KBrO₃ + 5 KBr + 6 HNO₃ → 6 KNO₃ + 3 Br₂ + 3 H₂O**Instructions:**Report your answer with three significant figures.**Answer Box:**[Input your answer here]

Given : KBrO3 + 5KBr +6HNO3 ----> 6KNO3 +3Br2 +3H2O Number of moles of Br2 = 0.828 mol Molar…

Answered: How many grams of KBrO3, 167.0 g/mol,…

How many grams of KBrO3, 167.0 g/mol, are required to prepare 0.828 moles of Br2 according to the balanced reaction? KBRO3 + 5 KBr + 6 HNO3 – 6 KNO3 + 3 Br2 + 3 H20

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Problem Statement:**

How many grams of KBrO₃, with a molar mass of 167.0 g/mol, are required to prepare 0.828 moles of Br₂ according to the balanced reaction?

**Chemical Reaction:**

KBrO₃ + 5 KBr + 6 HNO₃ → 6 KNO₃ + 3 Br₂ + 3 H₂O

**Instructions:**

Report your answer with three significant figures.

**Answer Box:**

[Input your answer here]

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