Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Content: Determining Major Product of a Chemical Reaction**
In organic chemistry, understanding the major product formed from a chemical reaction is crucial. Let's analyze the given problem and identify the correct major product.
**Question:**
What is the major product of the following chemical reaction?
![Chemical Reaction Image]
_Reaction Conditions:_
- Water (H₂O)
- Sulfuric acid (H₂SO₄)
- Mercuric sulfate (HgSO₄)
**Options:**
1. \[
\begin{array}{c}
\text{OH} \\
\text{H} \\
\text{CH₃}-\text{C}-\text{CH}= \text{CH} \\
\text{OH}
\end{array}
\]
2. \[
\begin{array}{c}
\text{CH₃}-\text{C}-\text{OH} \\
\text{H} \\
\end{array}
\]
3. \[
\begin{array}{c}
\text{CH₃}-\text{CO}-\text{CH₃} \\
\end{array}
\]
4. \[
\begin{array}{c}
\text{CH₃}-\text{CH₂}-\text{C}=\text{O} \\
\text{H}
\end{array}
\]
**Explanation:**
The given chemical reaction involves the hydration of an alkyne (specifically a methyl alkyne) in the presence of water, sulfuric acid, and mercuric sulfate. This is a common reaction in organic chemistry for converting alkynes to carbonyl compounds via keto-enol tautomerism.
1. Initially, the alkyne reacts with water to form an enol.
2. The enol then tautomerizes to a more stable keto form.
In this specific reaction, the triple bond of 2-butyne will undergo hydration to form a methyl ketone.
Given these options and the specific conditions, the major product of this reaction is the ketone form:
**Option 3:**
\[
\begin{array}{c}
\text{CH₃}-\text{CO}-\text{CH₃} \\
\end{array}
\]
**Conclusion:**
Given the information and conditions, the major product formed is 2-butanone (a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb00ff254-c89e-4d98-9f37-4465f02914e3%2F6b3fb39b-3982-4d68-9f83-ac37034a7c61%2Fdvp01xb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Educational Content: Determining Major Product of a Chemical Reaction**
In organic chemistry, understanding the major product formed from a chemical reaction is crucial. Let's analyze the given problem and identify the correct major product.
**Question:**
What is the major product of the following chemical reaction?
![Chemical Reaction Image]
_Reaction Conditions:_
- Water (H₂O)
- Sulfuric acid (H₂SO₄)
- Mercuric sulfate (HgSO₄)
**Options:**
1. \[
\begin{array}{c}
\text{OH} \\
\text{H} \\
\text{CH₃}-\text{C}-\text{CH}= \text{CH} \\
\text{OH}
\end{array}
\]
2. \[
\begin{array}{c}
\text{CH₃}-\text{C}-\text{OH} \\
\text{H} \\
\end{array}
\]
3. \[
\begin{array}{c}
\text{CH₃}-\text{CO}-\text{CH₃} \\
\end{array}
\]
4. \[
\begin{array}{c}
\text{CH₃}-\text{CH₂}-\text{C}=\text{O} \\
\text{H}
\end{array}
\]
**Explanation:**
The given chemical reaction involves the hydration of an alkyne (specifically a methyl alkyne) in the presence of water, sulfuric acid, and mercuric sulfate. This is a common reaction in organic chemistry for converting alkynes to carbonyl compounds via keto-enol tautomerism.
1. Initially, the alkyne reacts with water to form an enol.
2. The enol then tautomerizes to a more stable keto form.
In this specific reaction, the triple bond of 2-butyne will undergo hydration to form a methyl ketone.
Given these options and the specific conditions, the major product of this reaction is the ketone form:
**Option 3:**
\[
\begin{array}{c}
\text{CH₃}-\text{CO}-\text{CH₃} \\
\end{array}
\]
**Conclusion:**
Given the information and conditions, the major product formed is 2-butanone (a
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