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What is the major product of the following reaction? H H =C + HBr CH3 H CH; CH3 CH3 CH3-CH ċ-CH3 Br CH3 CH3 CH,-CH-C–CH3 Br Br ČH3

What is the major product of the following reaction? H H =C + HBr CH3 H CH; CH3 CH3 CH3-CH ċ-CH3 Br CH3 CH3 CH,-CH-C–CH3 Br Br ČH3

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** What is the major product of the following reaction? **Reaction:** - Ethylene (H\(_2\)C=CH\)-C(CH\(_3\))\(_2\)) + Hydrobromic acid (HBr) → **Options:** 1. **Option A:** \[ \begin{array}{c} CH_3 \\ CH_3-CH-C-CH_3 \\ | \\ Br \\ CH_3 \end{array} \] 2. **Option B:** \[ \begin{array}{c} CH_3 \\ CH_2-CH-C-CH_3 \\ | \\ Br \\ CH_3 \end{array} \] 3. **Option C:** \[ \begin{array}{c} CH_3 \\ CH_3-CH-C-CH_2Br \\ | \\ CH_3 \end{array} \] 4. **Option D:** \[ \begin{array}{c} CH_3 \\ CH_2-CH_2-C-CH_3 \\ | \\ Br \\ CH_3 \end{array} \] **Explanation of the Reaction and Options:** - The given reaction involves the addition of HBr to an alkene (propylene in this case). This is an example of an electrophilic addition reaction, where the pi bond of the alkene will break, and the H and Br will add across the double bond. - The most stable carbocation intermediate determines the major product. - The major product will generally follow Markovnikov's rule, where the hydrogen ion (H\(^+\)) from HBr adds to the less substituted carbon, and bromide ion (Br\(^-\)) adds to the more substituted carbon.
Transcribed Image Text:**Question:** What is the major product of the following reaction? **Reaction:** - Ethylene (H\(_2\)C=CH\)-C(CH\(_3\))\(_2\)) + Hydrobromic acid (HBr) → **Options:** 1. **Option A:** \[ \begin{array}{c} CH_3 \\ CH_3-CH-C-CH_3 \\ | \\ Br \\ CH_3 \end{array} \] 2. **Option B:** \[ \begin{array}{c} CH_3 \\ CH_2-CH-C-CH_3 \\ | \\ Br \\ CH_3 \end{array} \] 3. **Option C:** \[ \begin{array}{c} CH_3 \\ CH_3-CH-C-CH_2Br \\ | \\ CH_3 \end{array} \] 4. **Option D:** \[ \begin{array}{c} CH_3 \\ CH_2-CH_2-C-CH_3 \\ | \\ Br \\ CH_3 \end{array} \] **Explanation of the Reaction and Options:** - The given reaction involves the addition of HBr to an alkene (propylene in this case). This is an example of an electrophilic addition reaction, where the pi bond of the alkene will break, and the H and Br will add across the double bond. - The most stable carbocation intermediate determines the major product. - The major product will generally follow Markovnikov's rule, where the hydrogen ion (H\(^+\)) from HBr adds to the less substituted carbon, and bromide ion (Br\(^-\)) adds to the more substituted carbon.
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