What is the major product obtained from the following reaction? 1. 9-BBN 2. НООН, NaОН

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**Reaction Analysis and Major Product Formation**

*Reaction Question:*  
What is the major product obtained from the following reaction?

**Reaction Details:**  
- Reactant: Styrene (a vinyl group attached to a benzene ring)
- Reagents: 
  1. 9-BBN (9-Borabicyclo[3.3.1]nonane)
  2. H₂O₂ (hydrogen peroxide), NaOH (sodium hydroxide)

**Reaction Explanation:**

This is a hydroboration-oxidation reaction. The process consists of two main steps:

1. **Hydroboration:**
   - 9-BBN is used to add across the carbon-carbon double bond in a syn-addition manner.
   - The boron attaches to the less substituted carbon (anti-Markovnikov addition).

2. **Oxidation:**
   - The intermediate organoborane is then oxidized using hydrogen peroxide in the presence of sodium hydroxide.
   - The boron atom is replaced by a hydroxyl group (–OH), forming an alcohol.

**Major Product:**

The reaction results in the formation of an anti-Markovnikov alcohol. In this case, the hydroxyl group attaches to the less substituted terminal carbon of the vinyl group, leading to the formation of 2-phenylethanol as the major product.

This transformation is significant for its regioselectivity in converting alkenes to alcohols without rearrangement, allowing for the synthesis of primary alcohols from terminal alkenes.
Transcribed Image Text:**Reaction Analysis and Major Product Formation** *Reaction Question:* What is the major product obtained from the following reaction? **Reaction Details:** - Reactant: Styrene (a vinyl group attached to a benzene ring) - Reagents: 1. 9-BBN (9-Borabicyclo[3.3.1]nonane) 2. H₂O₂ (hydrogen peroxide), NaOH (sodium hydroxide) **Reaction Explanation:** This is a hydroboration-oxidation reaction. The process consists of two main steps: 1. **Hydroboration:** - 9-BBN is used to add across the carbon-carbon double bond in a syn-addition manner. - The boron attaches to the less substituted carbon (anti-Markovnikov addition). 2. **Oxidation:** - The intermediate organoborane is then oxidized using hydrogen peroxide in the presence of sodium hydroxide. - The boron atom is replaced by a hydroxyl group (–OH), forming an alcohol. **Major Product:** The reaction results in the formation of an anti-Markovnikov alcohol. In this case, the hydroxyl group attaches to the less substituted terminal carbon of the vinyl group, leading to the formation of 2-phenylethanol as the major product. This transformation is significant for its regioselectivity in converting alkenes to alcohols without rearrangement, allowing for the synthesis of primary alcohols from terminal alkenes.
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