What is the energy of a gamma photon of frequency 2.32 × 1020 X 10-13 J Hz?

Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
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**Question:**

What is the energy of a gamma photon of frequency \(2.32 \times 10^{20}\) Hz?

\[ \Box \times 10^{-13} \, \text{J} \]

**Explanation:**

To find the energy of a gamma photon, we use the formula:

\[ E = h \cdot f \]

where \( E \) is the energy, \( h \) is Planck’s constant (\(6.626 \times 10^{-34} \, \text{J}\cdot\text{s}\)), and \( f \) is the frequency of the photon.

Given:
- Frequency \( f = 2.32 \times 10^{20} \, \text{Hz} \)

Substituting the values into the formula:

\[ E = 6.626 \times 10^{-34} \, \text{J}\cdot\text{s} \times 2.32 \times 10^{20} \, \text{Hz} \]

Calculate \( E \) to complete the equation:

\[ E \approx 1.54 \times 10^{-13} \, \text{J} \]

Therefore, the blank in the original question should be filled with approximately 1.54.
Transcribed Image Text:**Question:** What is the energy of a gamma photon of frequency \(2.32 \times 10^{20}\) Hz? \[ \Box \times 10^{-13} \, \text{J} \] **Explanation:** To find the energy of a gamma photon, we use the formula: \[ E = h \cdot f \] where \( E \) is the energy, \( h \) is Planck’s constant (\(6.626 \times 10^{-34} \, \text{J}\cdot\text{s}\)), and \( f \) is the frequency of the photon. Given: - Frequency \( f = 2.32 \times 10^{20} \, \text{Hz} \) Substituting the values into the formula: \[ E = 6.626 \times 10^{-34} \, \text{J}\cdot\text{s} \times 2.32 \times 10^{20} \, \text{Hz} \] Calculate \( E \) to complete the equation: \[ E \approx 1.54 \times 10^{-13} \, \text{J} \] Therefore, the blank in the original question should be filled with approximately 1.54.
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