What is the edge length of a cube whose mass for aluminum is 3.44g? Density is 2.70 g/cm3 and Volume = edge length3 %3D O 1.58 cm O 1.07 cm O 2.51 cm O 1.89 cm O 2.01 cm
What is the edge length of a cube whose mass for aluminum is 3.44g? Density is 2.70 g/cm3 and Volume = edge length3 %3D O 1.58 cm O 1.07 cm O 2.51 cm O 1.89 cm O 2.01 cm
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Problem Statement:
**Question:**
What is the edge length of a cube whose mass for aluminum is 3.44g? Density is 2.70 g/cm\(^3\) and Volume = edge length\(^3\).
**Options:**
- 1.58 cm
- 1.07 cm
- 2.51 cm
- 1.89 cm
- 2.01 cm
### Explanation:
To solve this problem, we need to use the relationship between mass, density, and volume. The formula for density is given as:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
Rearranging the formula to solve for volume:
\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
Given:
- Mass = 3.44 g
- Density = 2.70 g/cm\(^3\)
Substitute the values into the equation:
\[ \text{Volume} = \frac{3.44 \, \text{g}}{2.70 \, \text{g/cm}^3} \]
After calculating the volume, since the volume of the cube is also the cube of the edge length (Volume = edge length\(^3\)), we need to take the cube root of the calculated volume to find the edge length.
### Answer:
Calculate the edge length by following the above steps and choose the correct option from the given choices.
**Correct edge length:**
\[ \text{Edge length} = 1.51 \, \text{cm} \]
So, after solving, the nearest option is 1.58 cm.
### Note:
This kind of problem helps students understand and apply fundamental concepts in physics and mathematics related to density, mass, and volume, fostering critical thinking and problem-solving skills.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb497b8c4-4d07-4c4c-ac55-469da516b240%2Fa06e5731-fff1-4c8f-a539-28e9f55cc13a%2F08kz5qu_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement:
**Question:**
What is the edge length of a cube whose mass for aluminum is 3.44g? Density is 2.70 g/cm\(^3\) and Volume = edge length\(^3\).
**Options:**
- 1.58 cm
- 1.07 cm
- 2.51 cm
- 1.89 cm
- 2.01 cm
### Explanation:
To solve this problem, we need to use the relationship between mass, density, and volume. The formula for density is given as:
\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]
Rearranging the formula to solve for volume:
\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
Given:
- Mass = 3.44 g
- Density = 2.70 g/cm\(^3\)
Substitute the values into the equation:
\[ \text{Volume} = \frac{3.44 \, \text{g}}{2.70 \, \text{g/cm}^3} \]
After calculating the volume, since the volume of the cube is also the cube of the edge length (Volume = edge length\(^3\)), we need to take the cube root of the calculated volume to find the edge length.
### Answer:
Calculate the edge length by following the above steps and choose the correct option from the given choices.
**Correct edge length:**
\[ \text{Edge length} = 1.51 \, \text{cm} \]
So, after solving, the nearest option is 1.58 cm.
### Note:
This kind of problem helps students understand and apply fundamental concepts in physics and mathematics related to density, mass, and volume, fostering critical thinking and problem-solving skills.
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