What is the E field at 13.3 cm from the center of the insulating sphere?
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The point r = 13.3 cm will lie outside the metallic shell
Electric field can be calculated by Gauss law by making a gaussian sphere of radius r = 13.3 cm
according to Gauss law
where ds is surface element. Qenclosed = net charge enclosed by sphere
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- A hollow conducting sphere has an inside radius of r1 = 0.17 m and an exterior radius of r2 = 0.27 m. The sphere has a net charge of Q = 5.4E-06 C. What is the field E1 in N/C 1 m from the sphere's exterior surface? What is the magnitude of the field at a distance of 0.05 m from the center of the sphere?What is the electric field due to a point charge of 25 ?C at a distance of 1 meter away from it?XUJI MA T B 2. A positive charge is located at the center of a cube.eq leups sendi otni bebloeg to Are the intersections of the field lines with a side of the box uniformly distributed across that side? Explain. ob o bobaan 918 210130 OVIM WOH 210SY BOTB A Bohus sn) AA madi ladal brs ISTRAL Wsiv obie od no od dor12 EM HW-88 Electric field and flux a. b. We can consider the left side of the box as composed of many small surface elements of equal area. i. Is the number of field lines through surface element A greater than, less than, or equal to VETERINDE and sostie sa the number of field lines through surface element B? Explain. REOS 0 que p vode 1310912 posts or to brida qol od rignonds xuftodel svoda nielque bri) sibbim edt deuotó xuft sdt of loups 10 anizz ii. Is the flux through surface element A greater than, less than, or equal to the flux through surface element B? Explain. c. Consider the surface element A itself as composed of many even smaller pieces. Would the number of field…
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- A thin conducting shell carries a charge of -2.8uC. The radius of the thin shell is a=1.90m. Find the electric field inside and outside the thin shell.The elctric field in the region is given by E = (8i + 2yj) N/C where y is in m. What is the magnitude of the electric flux through the top face of the cube shown?