College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Under the calculation portion of the included images for Ez electric field portion why is it xy^2 and not xy^2+4xy?

Transcribed Image Text:[Chapter 7, Problem 56P
In a particular region, the electric potential is given by V = -xy²z + 4xy . What is the electric field in this
region?
SAVE

Transcribed Image Text:To determine
The equation of electric field from the equation of electric potential.
Answer to Problem 56P
Ē = (y²z + 4y) i + (2xyz + 4x) j + (xy²) k
E
Explanation of Solution
Given:
Equation of electric potential, V = -xy²z + 4xy
Formula used:
Electric field components
Ꮩ
Ꮩ
-ov, E₁ = V₁ E₂ = - dv
Ey
Ez
Əx
dy
дz
Ex
Calculation:
Electric field components
==
Ex
Ey
Ez
Conclusion:
av
dx
av
дz
=
a(-xy²z+4xy)
dx
a(-xy²z+4xy)
dy
a(-xy²z+4xy)
dz
= y²z + 4y
=
2xyz + 4x
=
= xy²
Electric field vector in that region E
=
(y²z + 4y) i + (2xyz + 4x)j + (xy²) k.
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