What is the displacement of the object from 2 to 7 seconds? 10 8 6 E4 Position (m) 0 -4 -6 O 5 m O 12 m O - 12 m O-8 m O 0 m O 8 m O -5 m Position vs Time Time (s) O 10

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Understanding Displacement from Position vs. Time Graph

#### Question
What is the displacement of the object from 2 to 7 seconds?

#### Graph Explanation
The graph provided is a "Position vs. Time" graph, where the x-axis represents time in seconds (s) and the y-axis represents position in meters (m). The key points can be interpreted as follows:

1. From 0 to 2 seconds, the object's position is constant at 8 meters.
2. Between 2 and 4 seconds, the object’s position decreases linearly from 8 meters to 2 meters.
3. From 4 to 5 seconds, the position remains constant at 2 meters. 
4. At 5 seconds, the position is 2 meters, and it decreases to -4 meters by 7 seconds.
5. At 7 to 8 seconds, the position remains constant at -4 meters.
6. From 8 to 10 seconds, the position increases back up to 0 meters.

To determine the displacement between two specific points in time (in this case, from 2 to 7 seconds):

1. Identify the starting position at 2 seconds (which is 8 meters).
2. Identify the ending position at 7 seconds (which is -4 meters).

#### Calculation
Displacement is given by the difference in position from the initial to the final state:
\[ \text{Displacement} = \text{Final Position} - \text{Initial Position} \]
\[ \text{Displacement} = -4\,\text{m} - 8\,\text{m} = -12\,\text{m} \]

Thus, the displacement of the object from 2 to 7 seconds is -12 meters.

#### Answer Choices
- \( \quad \;\, 5 \, \text{m} \)
- \( \quad \, 12 \, \text{m} \)
- \( \quad -12 \, \text{m} \)
- \( \quad -8 \, \text{m} \)
- \( \quad \;\, 0 \, \text{m} \)
- \( \quad \;\, 8 \, \text{m} \)
- \( \quad -5 \, \text{m} \)

Based on the calculation above, the correct answer is:
\[ \boxed{-12\,
Transcribed Image Text:### Understanding Displacement from Position vs. Time Graph #### Question What is the displacement of the object from 2 to 7 seconds? #### Graph Explanation The graph provided is a "Position vs. Time" graph, where the x-axis represents time in seconds (s) and the y-axis represents position in meters (m). The key points can be interpreted as follows: 1. From 0 to 2 seconds, the object's position is constant at 8 meters. 2. Between 2 and 4 seconds, the object’s position decreases linearly from 8 meters to 2 meters. 3. From 4 to 5 seconds, the position remains constant at 2 meters. 4. At 5 seconds, the position is 2 meters, and it decreases to -4 meters by 7 seconds. 5. At 7 to 8 seconds, the position remains constant at -4 meters. 6. From 8 to 10 seconds, the position increases back up to 0 meters. To determine the displacement between two specific points in time (in this case, from 2 to 7 seconds): 1. Identify the starting position at 2 seconds (which is 8 meters). 2. Identify the ending position at 7 seconds (which is -4 meters). #### Calculation Displacement is given by the difference in position from the initial to the final state: \[ \text{Displacement} = \text{Final Position} - \text{Initial Position} \] \[ \text{Displacement} = -4\,\text{m} - 8\,\text{m} = -12\,\text{m} \] Thus, the displacement of the object from 2 to 7 seconds is -12 meters. #### Answer Choices - \( \quad \;\, 5 \, \text{m} \) - \( \quad \, 12 \, \text{m} \) - \( \quad -12 \, \text{m} \) - \( \quad -8 \, \text{m} \) - \( \quad \;\, 0 \, \text{m} \) - \( \quad \;\, 8 \, \text{m} \) - \( \quad -5 \, \text{m} \) Based on the calculation above, the correct answer is: \[ \boxed{-12\,
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