**Ordering Velocity over Time Graphs by Displacement**Consider the following velocity over time graphs. Order them by displacement during the time a line is shown on the graph. Order from least to greatest. ### Graph Descriptions:1. **Graph on the Left:** - **Line A:** - Starts at (0 s, 0 m/s) and ends at (25 s, 30 m/s). - **Line B:** - Starts at (0 s, 40 m/s) and ends at (25 s, 50 m/s).2. **Graph on the Right:** - **Line C:** - Starts at (0 s, 20 m/s) and remains constant until (25 s, 20 m/s). - **Line D:** - Starts at (0 s, 40 m/s) and remains constant until (25 s, 40 m/s).### Analysis:To find the displacement, calculate the area under each line:1. **Line A (Left Graph):** - A triangle with base = 25 s and height = 30 m/s. - Area = 1/2 * base * height = 1/2 * 25 s * 30 m/s = 375 m.2. **Line B (Left Graph):** - Trapezoid with the following bases and height: - Base 1: 40 m/s - Base 2: 50 m/s - Height: 25 s - Area = 1/2 * (Base 1 + Base 2) * height = 1/2 * (40 m/s + 50 m/s) * 25 s = 1/2 * 90 m/s * 25 s = 1125 m.3. **Line C (Right Graph):** - A rectangle with base = 25 s and height = 20 m/s. - Area = base * height = 25 s * 20 m/s = 500 m.4. **Line D (Right Graph):** - A rectangle with base = 25 s and height = 40 m/s. - Area = base * height = 25 s * 40 m/s = 1000 m.### Order Lines by Displacement (Least to Greatest):- A- C

Answered: Image /qna-images/answer/fde35093-2f05-40b3-bff2-462c14a01c31.jpg

Answered: Consider the following velocity over…

Consider the following velocity over time graphs. Order them by displacement during the time a line is shown on the graph. Order from least to greatest. 50----------||²||||| 50 DESTRU

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A student late to class runs at a constant 4.30 m/s to catch a bus. She reaches the bus stop 2.00 s after the bus starts from rest with an acceleration of 0.950 m/s2. Where and when does the student catch the bus? Here hint for equation
What is the relationship between acceleration and velocity?
A roof tile falls from rest from the top of a building. An observer inside the building notices that it takes 0.22 s for the tile to pass her window, which has a height of 1.13 m. How far above the top of this window is the roof? Number i Units
Please solve correctly!! Thank you
NEED EXPLANATION A particle moves so that its position x metres at time t seconds is given by x = 2t³ - 18t. (i) Calculate the position of the particle at times t = 0, 1, 2, 3 and 4. (ii) Draw a diagram showing the position of the particle at these times. (iii) Sketch a graph of the position against time. (iv) State the times when the particle is at the origin and describe the direction in which it is moving at those times. Answer: (i) 0m, 16m, -20m, 0m, 56m. -16 Position (m) 40 20 -20 0 0 56 4 Time 6) livl t=0 moving backwards, t = 3 moving forwards.
4. The graph above is the position-versus-time graph of an object. Which of the following is the velocity-versus-time graph of the object? (A) (В) V. al (D)
A particle's position is given by x = 6 − 9t + 1t2 (where t is in seconds and x is in meters).1. What is its velocity at t = 1 s? (Indicate the direction with the sign of your answer.)-----m/s2. What is its speed just then?-----m/s3. Is there ever an instant when the velocity is zero? If so, give the time t; if not, say NONE.
A truck starts from rest and accelerates at 0.8m/s^2. 7 s later, a car accelerates from rest at the same starting point with an acceleration of 3m/s^2.a) Where and when does the car catch the truck? __ m from the starting point
2. A ball is kicked straight up from ground level at a velocity of 13 m/s. Find: the maximum height the time at which thẻ ball reaches maximum height the time required for the entire trip e. f. g. h. the ball's vélocity just before it hits the ground upon returning
A dipole is held motionless in an electric field as shown in the figure. When the dipole is released, which of the following describes the subsequent motion? P The dipole rotates counterclockwise The dipole rotates clockwise and move more towards right side The dipole rotates counterclockwise and move more towards left side The dipole rotates counterclockwise and move more towards right side O The dipole rotates clockwise The dipole rotates clockwise and move more towards left side
Short computation The velocity of an object as a function of time is given by v(t) = b = ct- et²2, where v and t are in SI units. The other variables are given as b = 4.1 m/s, c = 4.1 m/s², and e = 1.5 m/s³. Determine the instantaneous acceleration of the object at time t = 0.38 s. a m/s² Remember to include a "-" if the acceleration turns out to be negative. Do not include a "+" for a positive value. Report your numerical answer below, assuming three significant figures.
Physics the interval of time of 5 to 7 seconds the object is moving to the left and has a negative velocity true false QUESTIONS Conteste Cierto o Falso La siguiente grafica muestra la descripoión del movimiento de un cuerpo en el eje de . Conteste certo o tao an premisan qu describen el movimiento del cuerpo en la grafica Temade de telge e En el intervalo de tiempo de 5a7 segundos el objeto se mueve hacaala quierda y tene velocidad negata True O Fele QUESTION S Conteste Ciertoo Falso La siguiente grafica muestra la descripción del movimiento de un cuerpo en el eje dex. Conteste cierto o falso a las premisas que describen el movimiento del cuerpo en la grafica. (m) 10 Tomado de Clege P Sah Eden Sefh En el intervalo de tiempo de 5 a 7 segundos el objeto se mueve hacia a la izquierda y tene velocidad negativa True O False