As a train accelerates away from a station, it reaches a speed of 4.8 m/s in 5.1 s. Part A For the steps and strategies involved in solving a similar problem, you may view the following Example 2-11 video: If the train's acceleration remains constant, what is its speed after an additional 6.0 s has elapsed? SOLUTION How fst is the boat moving aher accelerating for 5.00 s Express your answer in meters per second. να Αφ Brekwter 240 m/s V = m/s 20 - . Submit Previous Answers Request Answer

As a train accelerates away from a station, it reaches a speed of 4.8 m/s in 5.1 s. Part A For the steps and strategies involved in solving a similar problem, you may view the following Example 2-11 video: If the train's acceleration remains constant, what is its speed after an additional 6.0 s has elapsed? SOLUTION How fst is the boat moving aher accelerating for 5.00 s Express your answer in meters per second. να Αφ Brekwter 240 m/s V = m/s 20 - . Submit Previous Answers Request Answer

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Short computation The velocity of an object as a function of time is given by v(t) = b = ct- et²2, where v and t are in SI units. The other variables are given as b = 4.1 m/s, c = 4.1 m/s², and e = 1.5 m/s³. Determine the instantaneous acceleration of the object at time t = 0.38 s. a m/s² Remember to include a "-" if the acceleration turns out to be negative. Do not include a "+" for a positive value. Report your numerical answer below, assuming three significant figures.
A stone is thrown straight upward and returns to the thrower hand after being 4.20s in the air. a) with that speed was the stone thrown. b) what maximum height did the stone reach. c) if a second stone was thrown at an angle 63.0 degrees above the horizontal, and reached the same maximum height as the first stone in part b what was the initial speed the second stone.
Please help! Required information: A cheetah can accelerate from rest to 52.9 m/s in 2.00 s. Assume that the acceleration is constant over the time interval. a) What is the magnitude of the acceleration of the cheetah? b) What is the distance traveled by the cheetah in these 2.00 s? c) A runner can accelerate from rest to 7.30 m/s in the same time, 2.00 s. What is the magnitude of the acceleration of the runner? d) A runner can accelerate from rest to 7.30 m/s in the same time, 2.00 s. By what factor is the cheetah’s average acceleration magnitude greater than that of the runner?
Part A A motorcycle moves according to the velocity-versus-time graph shown in the figure(Figure 1). Find the average acceleration of the motorcycle during segment A of the motion. Express your answer using two significant figures. ? m/s Submit Request Answer Part B Find the average acceleration of the motorcycle during segment B of the motion. Express your answer using two significant figures. ap = m/s? Submit Request Answer Figure 1 of 1 Part C 15 Find the average acceleration of the motorcycle during segment C of the motion. 10 Express your answer using two significant figures. A 5 ac = m/s? 5 10 15 20 25 Time, t (s) Submit Reauest Answer s/w) a 'Ápoja
Can I get some help on part (c) sketching a position time graph of the data above and also can you justify whether or not a line fits the data on the position time graph please.
Must use info from textbook to be able to solve problem
b) By looking Figure 2, how can we say about velocity change with respect to time for every point (a, b, c, d, e, f, g, h, I, j, k, l)? Which points have the bigger instantaneous velocity? You should show the reason why you are using any parameter in the calculations. Time t Figure 2 1 Position x
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Constant The acceleration of a stone is given by az (t) = -2.04 m/s + (3.10 m/s )t. %3D Part A What is the initial velocity VOz such that the stone will have the same x-coordinate at time t = 3.90 s as it had at t =0. Express your answer in mneters per second. ΑΣΦ m/s Submit Request Answer Part B Find the velocity at time t = 3.90 s? Express your answer in meters per second. ΑΣΦ m/s